ABC is scalene triangle. Its angle A is kept constant, rest sides are tripled in length such that AC'=3AC and AB'=3AB. how much is the area increased in triangle AB'C' from ABC?
1)800% 2)850% other options i don't remeber

• Ans: 800%
  
  Scalene Triangle-
  A triangle with all sides of different lengths and different angle.
  Let us assume triangle(ABC) having sides 3,4,5 and angle A = 90degree.
  Hence Ar(ABC) = 1/2 * 3* 4 = 6.
  Similarly, assume triangle AB'C' where AB' = 3AB, AC' = 3AC' (A/Q)
  Hence Ar(AB'C) = 1/2 * 9 * 12 = 54.
  
  Difference = 54-6 = 48.
  % CHANGE = 48 * 100/ 6 = 800% Ans :-)..;
• 9 years agoHelpfull: Yes(32) No(2)
• sorry ...area increase 800%(((54-6)/6)*100=800)
• 9 years agoHelpfull: Yes(7) No(0)
• let any right angle triangle whose size(3,4 & 5)---->also called scalene triangle because size r different
  then Area=1/2*base*height=0.5*3*4=6
  take any angle cont.(i take 90 angle constant..)
  then sides r=9,12,15(After increase three times two sides,then also increase third side)
  hence,Area=0.5*9*12=54
  AREA INCREASED BY 900%
  
• 9 years agoHelpfull: Yes(6) No(6)
• for clear understand implemate in picturally
  TRAINGLE AB'C' is divided then 3 parallograms
  and 3 triangle of ABC area
  each parallogram is 2 times of ABC area
  3 parallogram =6 times of ABC
  so 600+300=900
  so answer is
• 9 years agoHelpfull: Yes(0) No(3)
• Answer : the five digit no. X will be divisible only when it has 5 "or" 0 in the one's position .. and the a five digit no. is possible when the one's position is 0, 1, 2, 3, 4 ,5 ,6 ,7 , 8, 9 ..i.e, in 10 ways ..but for divisibility from 5 there are 5 cases possible when in these digits are in one's position 1=> 1+4=5 , 3=>1+4=5,7=>1+4=5,9=>1+4=5
  So, 4/10 = 2/5 Answer
• 9 years agoHelpfull: Yes(0) No(0)