the ratio of the length : breadth :height of cuboid is 5:4:3 the volumeof 7500 what will be the surface area of the bar

• volume= 5x X 4x X 3x=7500
  so, x=5
  5x=25, 4x= 20, 3x=15
  suface area= 2(lb + bh + hl)= 2(25X20 + 20X15 + 15X25) = 2350
• 8 years agoHelpfull: Yes(10) No(0)
• volume= 5x X 4x X 3x=7500
  so, x=5
  5x=25, 4x= 20, 3x=15
  suface area= 2(lb + bh + hl)= 2(25X20 + 20X15 + 15X25) = 2350
• 8 years agoHelpfull: Yes(5) No(0)
• Let the Length, Breadth and Height of Cuboid is 5X, 4X, 3X.
  Volume = 7500
  5X * 4X * 3X = 7500
  60 X^3 = 7500
  X^3 = 750/6
  X^3 = 125
  X = 5
  Therefore Length = 25, Breadth = 20, Height = 15
  Surface Area = 2(Length + Breadth + Height)
  Surface Area = 2(60)
  Surface Area = 120
• 6 years agoHelpfull: Yes(2) No(7)
• 1^3+1=2
  2^3+2=10
  3^3+3=30
  4^3+4=68
  so 5 = 5^3+5=130 is the ans
• 5 years agoHelpfull: Yes(0) No(4)
• 5x*4x*3x=60x^3
  60x^3=7500
  x^3=7500/60
  x^3=125
  x=5
  surface area =2(l+b+h)
  volume=2(5*5+4*5+3*5)
  2(60)
  120
• 4 years agoHelpfull: Yes(0) No(1)