x is a two digit palindrome
y is a three digit palindrome

x+y=z

find the middle digit of y?

a. z is a 4 digit palindrome.
b. z is an odd number.

options:
a. can be solved by one option but canot be solved by other one alone.
b. can be solved by either option.
c.can be sovled only by both the option.
d. canot be solved by either option.

• 22+979=1001
  
  A
• 8 years agoHelpfull: Yes(18) No(4)
• assuming case 1 i.e. z is a 4-digit palindrome.
  This information is sufficient to find the middle digit of y.
  Here's how :-
  for z to be a 4 digit number, the hundreds digit of 'Y' MUST be 9 (else you won't get a 4-digit number coz 'x' is of 2 digits & 'y' of 3 .... Also since y is a palindrome ,units digit of y also = 9 ) .
  Also since z is 4 digits, and y is 9_9 , the 2-rightmost digits of z must be 10, i.e. z = 10_ _ (since y = 9_9 , for any value of x, there can only be a carry of 1 in the hundred's place, & 9+1 = 10).
  Since z is a pallindrome z = 1001.
  Now z = 1001 , and x = z - y, or x = 1001 - 9_9 .
  so ,
  1 0 0 1
  - 9 _ 9
  --------
  _ 2
  
  But x is a pallindrome. hence x = 22 and hence y = 979.
• 8 years agoHelpfull: Yes(6) No(0)
• option D it cannot be solved by either option as both the statemnts are insuufcient
  take any 2 digit palindrome no like 44,55 etc and three digit palindrome like 101,999 and check.
• 8 years agoHelpfull: Yes(5) No(11)
• x=111 y=1111 x=y=z
  111+1111=1222 so ans is d
• 8 years agoHelpfull: Yes(2) No(6)
• option d ..data in sufficient
• 8 years agoHelpfull: Yes(2) No(2)
• @nelson 22 is not a palindrome.then how the ans will b?
• 8 years agoHelpfull: Yes(2) No(1)
• Let us Assume with putting value to context
  x is a two digit palindrome::99
  y is a three digit palindrome:999
  x+y=z
  99 + 999 = 1098
  a. false
  b.false
  so,option d
  so middle disit
• 8 years agoHelpfull: Yes(1) No(2)
• both the options gives alot of value for example-22+111=133,22+979=1001 so we get alot of values we are not getting single value so ans is :d
• 8 years agoHelpfull: Yes(0) No(2)
• Correct answer is A.
  Their is only 1 number that satisfies 1st condition.
  x=22 and y=979
  x+y=22+979=1001 (palindrome number)
• 6 years agoHelpfull: Yes(0) No(0)
• Answer is (D) Cannot be solve by either options
  x=11,22,33.....99
  y=121,212.....989
  In question it is given that z is odd . Thus, even+odd=odd(z)
  let x=88 y=989 x+y=1077(odd)
  let x=22 y=979 x+y=1001(odd)
  Thus, y can be any no. so cannot determine the middle digit of y.
• 5 years agoHelpfull: Yes(0) No(2)
• X^3(1-x^2)
• 4 years agoHelpfull: Yes(0) No(0)