The age of the two friends were in the ration of 6:5. If the sum of their ages is 66. Then after how many years their ratio will become 7:6?

• Let AGE of two friends = A:B = 6:5
  SUM of ages = 6x+5x = 66
  11x = 66 ----> x=6
  ages of friends = 6x = 36
  5x = 30
  
  let Y be no.of years after which their age ratio is 7:6
  (36+Y) : (30+Y) = 7:6
  By solving we get Y =6
  
  Hence no.of years = 6 aftr which their age ratio is 7:6
  
• 9 years agoHelpfull: Yes(25) No(0)
• 6:5, 6x+5x=66
  So x=6
  36+n/30+n == 6/5
  thus n==6
• 9 years agoHelpfull: Yes(1) No(1)
• Ans :- 6 years
  
  
  Age of two friends are in the ratio 6:5
  And their sum is 66
  So 6x+5x=66
  11x=66
  X=6
  
  Now suppose after y years their ration of ages become 7:6
  
  On solving we get
  (6x+y)/(5x+y) =7/6
  Substituting x=6
  
  We get value of y as 6 years .
• 9 years agoHelpfull: Yes(1) No(0)
• a+b=66, a=6 , b=5 , and b=6b/5
  then a=36, b=30
  Add 6 to a and b, then the ratio will be 7:6 .
  After 6 years their ages will be 7:6
  
  
• 9 years agoHelpfull: Yes(0) No(0)
• x/y=6/5 => x=6y/5
  x+y=66 => 6y/5+y=66 =>6y+5y=66*5 ==> y=30 so x=36
  After 6 years x=42 and y=36 so x/y=42/36 = 7/6
  So answer is 6 years.
• 9 years agoHelpfull: Yes(0) No(0)
• Solution: 6x+5x=66, so x=6, put first ratio after substitution is (6*6)/(5*6) and second ratio is 36/30 and 42/36 So difference in numerators 42-36=6 years
  Ans will be 6 years
• 9 years agoHelpfull: Yes(0) No(0)
• by given data thier ages can be( 6/11)*66=36 and the other one is 30
  so after x years their ages ill be in ratio 7:6
  therefore (36+x)/(30+x)=7:6
  by solving it x=6 years
• 9 years agoHelpfull: Yes(0) No(0)
• 6x+5x=66
  11x=66
  X=6 then
  36+x/30+x= 7/6
  By solving it we get x=6
  Ans is 6 years
• 9 years agoHelpfull: Yes(0) No(0)