In the island of punycity license plates for cars consists of 3 letters. 2 license plates are considered if
and only if they contain the same 3 letters in the same order .How many punycity license plates are
possible if the letter Q cannot occur as the last character and can only occur when the letter immediately
after it is U ?
a)17575 b)15625 c)15675 d)17650

• we have 26 letters.
  so without Q now we have 25 letters.
  so the license consist of 3 letters.
  so now no of combinations can be possible 25*25*25=15625.
  now if u put q in the license then it must like this
  Q U _ = for this combination we have 25 values
  _ Q U = for this combination we have 25 values
  now the total combinations will be=15625+25+25=15675. :)
• 8 years agoHelpfull: Yes(35) No(1)
• What does that mean - - "2 license plates are considered if
  and only if they contain the same 3 letters in the same order"??
• 8 years agoHelpfull: Yes(2) No(0)
• I think since it is given Q can only be there if U is just after it
  Case 1: Q is followed by U keeping in mind Q can't occupy lst place
  Q U 25ways to fill third place
  25 ways to fill 1 position Q U.
  Here see Q is not occupying the 3 place..
  Case 2: when Q is not included
  25*25*25
  Adding both case we have ans 15675
• 8 years agoHelpfull: Yes(2) No(0)
• Does anyone remember this qn..plzz post solution
• 8 years agoHelpfull: Yes(0) No(0)
• Bt in qustn Q is nt possible as last digit gourab dutta
• 8 years agoHelpfull: Yes(0) No(1)
• @CHAITALIBANERJEE gourab has taken three cases & in none of the case, he has taken Q as last digit... In which r u facing problem??
• 8 years agoHelpfull: Yes(0) No(0)
• 15625
  
  25*25*25=15625 no Q
  UQ_--->25 ways to fill letter in last field
  
  15625+25=15650
• 8 years agoHelpfull: Yes(0) No(2)