4 men throw a die each simultaneously. Find the probability that at least 2 people get the same number
a. 5/18
b. 13/18
c. 1/36
d. 1/2

• Explanation:
  The number of ways of rolling a dice where no two numbers probability that no one rolls the same number = 6 x 5 x 4 x 3
  Now total possibilities of rolling a dice = 64
  The probability that a no one gets the same number = 6×5×4×3 / 6^4 = 5/18
  So the probability that at least two people gets same number = 1−5/18=13/18
• 8 years agoHelpfull: Yes(21) No(5)
• b)13/18
  P=1-(6*5*4*3)/(6*6*6*6)
• 8 years agoHelpfull: Yes(5) No(0)
• ans is option B=13/18
  
• 8 years agoHelpfull: Yes(2) No(3)
• 6. If 3
• 8 years agoHelpfull: Yes(0) No(2)
• Let's first find the probability that all the people get different numbers.
  
  Outcome of each die can be any of the 6 numbers. Therefore,
  Total number of outcomes
  =
  6
  4
  
  
  First die can give any of the 6 numbers
  Second die can give any of the remaining 5 numbers
  Third die can give any of the remaining 4 numbers
  Fourth die can give any of the remaining 3 numbers
  Therefore, total favorable outcomes 6×5×4×3
  
  P(all people get different numbers)
  =
  6
  ×
  5
  ×
  4
  ×
  3
  6
  4
  =
  5
  18
  
  
  P(at least 2 people get the same number)
  =
  1
  −
  5
  18
  =
  13
  18
• 4 years agoHelpfull: Yes(0) No(0)