A train travelling at a constant rate of 80 KMPH enters a tunnel 7 KM long at precisely 5 12

1 KM is the correct answer.
9 years agoHelpfull: Yes(2) No(0)
S=d/t=>here let the length of tunnel be x and convert min to hours ie 5:12 to 5:18 6 min to 6/60 hrs then,as per formula 80 =(7+x)/6/60;then on solving 10 =10x..=> length is 1km
9 years agoHelpfull: Yes(0) No(0)
S=d/t=>here let the length of train be x and convert min to hours ie 5:12 to 5:18 6 min to 6/60 hrs then,as per formula 80 =(7+x)/6/60;then on solving 10 =10x..=> length is 1km.
9 years agoHelpfull: Yes(0) No(0)
Say length of train be x
total distance traveled by the train is (7000+x) metres in (5:18-5:12)= 6min= 360sec
train travels in 1sec 80*5/18 m
train travels in 360 sec 80*5*360/18 = 8000 m
therefore 7000+x = 8000 ; x= 1000 m or 1km
9 years agoHelpfull: Yes(0) No(0)
ANSWER IS OPTION D.................
9 years agoHelpfull: Yes(0) No(0)
option d
distance of train be x,distance of tunnel be 7kmthen speed= distance/time==>80=(7+x)/time taken to travel i-e 6 mins==>6/60 hrs==>80=(7+x)/6/60 hours==10= 10x==>1km
9 years agoHelpfull: Yes(0) No(0)
let distance of train=x
7+x/1/10=80
70+10x=80
x=1km
9 years agoHelpfull: Yes(0) No(0)
ans 1km
d=st=80*6/60=8km
d=length of train+length of tunnel
so length of train=8-7=1km
5 years agoHelpfull: Yes(0) No(0)

A train travelling at a constant rate of 80 KMPH enters a tunnel 7 KM long at precisely 5/;12 AM .At 5:18 AM the end of the train exits the tunnel .The length of the train in KM is
a)1.5 b)1.2 c)2 d)1