A train travelling at a constant rate of 80 KMPH enters a tunnel 7 KM long at precisely 5/;12 AM .At 5:18 AM the end of the train exits the tunnel .The length of the train in KM is
a)1.5 b)1.2 c)2 d)1

• ans-d
  let the length of the train is x km
  total distance covered by train=length of train+length of tunnel
  =(x+7)km
  total time to cover tunnel=6minute=6/60hours
  now,we can say
  (x+7)/80=6/60
  x=1km
• 8 years agoHelpfull: Yes(11) No(0)
• 1 KM is the correct answer.
• 8 years agoHelpfull: Yes(2) No(0)
• S=d/t=>here let the length of tunnel be x and convert min to hours ie 5:12 to 5:18 6 min to 6/60 hrs then,as per formula 80 =(7+x)/6/60;then on solving 10 =10x..=> length is 1km
• 8 years agoHelpfull: Yes(0) No(0)
• S=d/t=>here let the length of train be x and convert min to hours ie 5:12 to 5:18 6 min to 6/60 hrs then,as per formula 80 =(7+x)/6/60;then on solving 10 =10x..=> length is 1km.
• 8 years agoHelpfull: Yes(0) No(0)
• Say length of train be x
  total distance traveled by the train is (7000+x) metres in (5:18-5:12)= 6min= 360sec
  train travels in 1sec 80*5/18 m
  train travels in 360 sec 80*5*360/18 = 8000 m
  therefore 7000+x = 8000 ; x= 1000 m or 1km
  
  
• 8 years agoHelpfull: Yes(0) No(0)
• ANSWER IS OPTION D.................
• 8 years agoHelpfull: Yes(0) No(0)
• option d
  distance of train be x,distance of tunnel be 7kmthen speed= distance/time==>80=(7+x)/time taken to travel i-e 6 mins==>6/60 hrs==>80=(7+x)/6/60 hours==10= 10x==>1km
• 8 years agoHelpfull: Yes(0) No(0)
• let distance of train=x
  7+x/1/10=80
  70+10x=80
  x=1km
• 8 years agoHelpfull: Yes(0) No(0)
• ans 1km
  d=st=80*6/60=8km
  d=length of train+length of tunnel
  so length of train=8-7=1km
• 4 years agoHelpfull: Yes(0) No(0)