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Algebra
In the polynomial f(x) =2*x^4 - 49*x^2 +54, what is the product of the roots, and what is the sum of the roots (Note that x^n denotes the x raised to the power n, or x multiplied by itself n times)?
a) 27,0
b) 54,2
c) 49/2, 54
d) 49, 27
Read Solution (Total 6)
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- Given equation: 2*x^4 +0*x^3 - 49*x^2 +0*x +54
let x1 and x2 be two roots of the equation then
sum of roots is x1+x2= (-b)/a= 0/2=0
and product is given by x1 * x2 = c/a=54/2=27 - 9 years agoHelpfull: Yes(10) No(0)
- Ans is (a) 27,0
- 9 years agoHelpfull: Yes(5) No(3)
- let x1 and x2 be two roots of the equation then
sum of roots is x1+x2= (-b)/a= 49/2
and product is given by x1 * x2 = c/a=54/2=27 - 9 years agoHelpfull: Yes(5) No(8)
- X1+X2= -B/A=0/2=0 ( Here B is 0)
X1X2= C/A = 54/2=27
(A) is the Answer - 9 years agoHelpfull: Yes(3) No(0)
- Equation for this type, ax4+bx3+cx2+dx+e
(2x^4+0x^3+-49x^2+0x+54)
formula
sum of roots =-ba=-02=0
products of roots=ea=542=27
27,0
Hope its help you.pleasure - 5 years agoHelpfull: Yes(1) No(0)
- Given equation: 2*x^4 +0*x^3 - 49*x^2 +0*x +54
let x1 and x2 be two roots of the equation then
sum of roots is x1+x2= (-b)/a= 0/2=0
and product is given by x1 * x2 = c/a=54/2=27
option a) - 5 years agoHelpfull: Yes(0) No(0)
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