given the digits 1,3,6,9 find the probability that a 3 digit number formed by using them with no digit repeated is divisible by 4 a)1/12 b)1/4 c)1/6 d)none

• ans will be 1/4
• 9 years agoHelpfull: Yes(14) No(2)
• Sorry 6/24=1/4
• 9 years agoHelpfull: Yes(10) No(1)
• the numbers can b 16,36,96,so unit digit can be filled in 1 way wheareas 10's place can be filled in 3 ways and hundred's place in 2 ways,so 2x3x1/4!=6/24=1/6
• 9 years agoHelpfull: Yes(9) No(16)
• 316,916,136,936,196,396 are the six numbers that can be formed divisible by 4 ... total no. of numbers that can be formed are 24.... 6/24 = 1/4
• 9 years agoHelpfull: Yes(7) No(0)
• divisibility rule for four is last 2 digit must be divisible by 4. so last 2 digit must be 16,36,96.
  (1) -- -- 1 6,(2) -- -- 3 6 , (3) -- -- 9 6
  mow you can put in 1 st case 9,3 yoy have 2*1 choice, similar in 2nd and 3rd case ..so total number of choice is =6
  and total no. odf case = 4!=24
  p(divisible 4)= 6/24=1/4
• 9 years agoHelpfull: Yes(6) No(1)
• For divisibility by 4, last 2 digits must be divisible by 4. The last 2 digits can be either 16 or 36.
  For units place, only 6. So no. of ways = 1
  For tens place, 1 or 3, so number of ways = 2
  For hundreds place, number of ways = 2 (since repetition not allowed)
  So total no. of ways = 1x2x2= 4
  Total possibilities = 4x3x2= 24
  reqd. probability = 4/24= 1/6
• 9 years agoHelpfull: Yes(3) No(5)
• For a number to be divisible by 4 the unit's and tenths places together must be divisible by 4.
  So the last 2 digits must be either 16 or 36 or 96. And repetition is not allowed so, the 100th place can be filled using other 2 no.s. So the answer is 3x2/4!
• 9 years agoHelpfull: Yes(2) No(0)
• sample space = 4*3*2= 24 ................................... using the concept of P&C.
  for no to be divisible by 4 last digit must be 6 (in this case only)
  total such no =6.................................. (6=3*2*1)
  therefore prob = 6/24 = 1/4.
• 9 years agoHelpfull: Yes(0) No(0)