I just finished 3 marble games & have 21 marbles.In the 1st game I lost half of my marbles.Inthe 2nd game I won 11 times what I had at the end of the 1stgame.In the 3rd game I won 9 marbles.How many marbles Did I have when I started playing?
a)6 b)4 c)8 d)2

• I think ans is 2.let no of marble be x
  After 1 game marble =x/2
  In 2 game 11*x/2
  In third 9
  So total he have 21 in end adding all equating
  9+11x/2+x/2=42
  Ans 2
• 9 years agoHelpfull: Yes(14) No(2)
• Let initially he has x marble
  At the end of 1 game marbel he has=x/2
  At end of 2nd game, marble he has=x/2 + 11x/2 = 6x
  Afte 3rd game marbel he has= 6x+9
  So equating we have
  6x+9=21
  X=2
  
• 9 years agoHelpfull: Yes(8) No(0)
• RICHA your answer is correct. but i think equation equating to 42 is not correct.
  i think equating the expression to 21 will give the answer as 2.
• 9 years agoHelpfull: Yes(3) No(0)
• d,assume intially x then half of it and multiplied 11 times and add 9 to it
• 9 years agoHelpfull: Yes(1) No(0)
• @ Richa
  Pls tell Why equating the equation to 42?
  What is the reason of 42?
  
• 9 years agoHelpfull: Yes(1) No(0)
• from the options we can verify easily.....
  2/2=1.............................................. lost half of his marbles
  1+(1*11)=12................................... won 11times what he had in 1st game
  12+9=21............................................. won 9 marbles more
• 9 years agoHelpfull: Yes(0) No(0)
• Answer is option (d) - 2.
  let initially I have 2 marbles then,
  after 1st game - 1 is remaining
  after 2nd game- 1+11*1=12 total
  after 3rd game- 12+9 = 21 total is remaining which is equal to 21 marbles as per question...hope it is easy to get
• 9 years agoHelpfull: Yes(0) No(0)
• Guys it was 21 only by mistake I write it 42
• 9 years agoHelpfull: Yes(0) No(0)
• let there be x marble initially after 1st game he left with x/2
  in second game he wn 11time so ans be x2+11*x/2=6x
  in third game he won 9 marbel so 6x+9=21=2 ans
• 9 years agoHelpfull: Yes(0) No(1)
• Let x be the initial ni of marbles. In 1st game he lost half, so he has x/2 with him. In the second game he won 11 times of what he had in 1st ,I.e. 11x/2, in 3rd he win 9. So eq will be (x/2)+(11x/2)+9=21.
  So ans is 2
• 9 years agoHelpfull: Yes(0) No(0)