.A pair of 8 slided dice has sides numbered 1 to 8.Each side has same probability or chance of landing face up.The probability that the product of 2 numbers on the sides that land face up exceeds 36 is
a)11/64 b)5/32 c)3/16 d)1/4

• total possibble combination=8c1*8c1=8*8=64
  total possible combinations that exceeds 36=(5,8),(6,7),(6,8),(7,6),(7,7),(7,8),(8,5),(8,6),(8,7),(8,8)=10
  the probability=10/64=5/32
• 9 years agoHelpfull: Yes(18) No(1)
• b ) 10/(8*8)
  10/64=5/32
  
• 9 years agoHelpfull: Yes(4) No(3)
• Only Possible results in the output buffer are:(5,8),(6,7),(6,8)....(8,8).
  therefore total number of desired output=11
  total number of possible results are 8*8=64
  therefore required ans=10/64=5/32
• 9 years agoHelpfull: Yes(1) No(0)
• probability become 5/32
• 9 years agoHelpfull: Yes(0) No(0)
• Total no of posssible outcome is 8*8 = 64 possible combination 10 so p =5/32
• 9 years agoHelpfull: Yes(0) No(0)
• total possibles=64 bcz 8 sided so 8 pow 2=64
  product of 2 nos should exceeds 36 so possible combination are
  (8,5)(8,6)(8,7)(8,8)(7,6)(7,7)(7,8)(6,7)(6,8)(5,8) so 10/64=5/32
• 6 years agoHelpfull: Yes(0) No(0)