.Adarsh went to a casino with Rs.6400 and played a certain game 6 times.Each time he bet half the money he had the time the chance of winning this game was ½ and adharsh won three of the 6 games even though he did not remember which 3 games he won.In each of these games he won the amount equal to his bet.After the 6 games the money was
a)3200 b)2700 c)1280 d)cannot be

• Which of three game he loss is not given here.
  So, Amount of money he have after playing 6 times it's Can Not Be Determined..
• 8 years agoHelpfull: Yes(9) No(2)
• 2700
  1) half of 6400 = 3200 he bet 3200 and won 3200 thus total 9600
  2) half of 9600 = 4800 he lost in bet.
  3) half of 4800= 2400he bet and he won 2400 thus total is 7200
  4) half of 7200= 3600 he lost in bet
  5) half of 3600=1800 he bet and won 1800 thus total is 5400
  6) half of 5400-2700 he lost in bet thus final total is 2700.
  
• 8 years agoHelpfull: Yes(3) No(15)
• @anil is right,
  In any of the case he is left with 2700
  Thus answer is 2700
• 8 years agoHelpfull: Yes(0) No(0)
• We can assume any no. Of event to be a win or a loss. The result is always same.
  Let us consider that he lost first 3 consecutive games and won last 3.
  Amount remaining after 3 loss= 6400*(1/2)*(1/2)*(1/2)=800
  Amount after winning in round 4= 400+(400*2)=1200
  Amt after win in round 5= 600+(600*2)=1800
  Amt after win in round 6= 900+(900*2)=2700 Ans.
• 6 years agoHelpfull: Yes(0) No(0)