Two cars starts from a & b and travel towards each other at speeds 0f 59 kmph and 60 kmph respectively at the time of their meeting the second car has travelled 120km more than the first the distance between a & b in kms is a)720 b)1230 c)1320 d) 600

• since time is const... so distance is directly proportional to speed.
  let 1st car travelled X distance...so 2nd car will travel (X+120).
  therefore X/(X+120)=59/60
  => X=7080
  total distance b/w A and B is (X+X+120)=14280kms
• 8 years agoHelpfull: Yes(19) No(11)
• let distance travelled by 1st >> X
  let distance travelled by 2nd >> X+120
  (X+120)/60 =(X)/59 .........................since time constant
  X=120
  distance between a & b is
  X + X+120 =360
  according to options......... multiple of 360 is 720
  ans is A
  
• 8 years agoHelpfull: Yes(5) No(8)
• Sorry guys mis typed
  X+X+120 =1320 is the ans
• 8 years agoHelpfull: Yes(1) No(8)
• taking speed of a 50km/hr
  x/x+120=50/60
  x=600
  total=x+x+120=1200+120=1320
• 8 years agoHelpfull: Yes(1) No(0)
• I think there is some mistake if speed of first car is 50 then only it satisfies given option.
  Let speed of car a =x so for car b =120+x
  S=D/T
  x/50=x+120/6
  Solving x=600
  For car B 600+120
  So distance 720
• 8 years agoHelpfull: Yes(0) No(7)
• Sorry guys mis typed
  X+X+120 =1320 is the ans
• 8 years agoHelpfull: Yes(0) No(4)
• Sorry guys mis typed
  X+X+120 =1320 is the ans
• 8 years agoHelpfull: Yes(0) No(6)
• 720 is the right answer
• 8 years agoHelpfull: Yes(0) No(0)