Two workers one young one old live together and work at same office it takes 20 minutes for the young to walk to office ald men takes 30 minutes for the same distance when will the young may catch up with old man if the old man starts at 10:05 am? A)10:10 b)10:15 c)10:25 d)10:20

• this is not so complicated as I have seen Priya did it
  10:05+0:30=10:35
  10:35-0:20=10:15
• 9 years agoHelpfull: Yes(5) No(1)
• 
  
  From the condition we know that the old man passes 1/30 of the way in 1 minute. So in 5 minutes, he'll pass 1/6
  
  So we could think of the problem like this. They both start at the same time, but the old man need to pass 5/6 of the way, while the young man should walk whole way. We aleady know that the old man pass 1/30 of the way in a minute, while the young man pass 1/20 of the way in a minute. So we need to find solution to the following equation:
  
  1−(1/20)t=5/6−(1/30)t
  1−t/20=5/6−t/30
  1−5/6=(1/20−1/30)t
  
  1/6=1/60t
  ⟹t=10
  
  
  So they'll meet 10 minutes after the young man starts his journey, i.e in 10:15am.
  
• 9 years agoHelpfull: Yes(4) No(3)
• Just take the hcf of 20 and 30min .
  We get 10
  Add 10min to 10:05
  We get 10:15
  Ans= 10:15
• 5 years agoHelpfull: Yes(1) No(0)