jake can dig a well in 16 days paul can dig the same well in 24 days.jake,paul and hari together dig the well in 8 days. Hari alone can dig the well in a)48 days b)24 days c)96 days d)32 days

• 1/16+1/24+h=1/8
  h=1/8-(1/16+1/24)
  =1/48.
  answer: a)48 days
• 9 years agoHelpfull: Yes(3) No(0)
• jack one day efficiency is 6.25%
  paul one day efficiency is 4.16%
  total efficiency of jack,paul,hari is 12.5%
  hari efficiency is 12.5-(6.25+4.16)=2.09%
  therefor time taken by hari=100/2.09=48 days
  
• 9 years agoHelpfull: Yes(1) No(0)
• jake's 1 day work is 1/16
  paul's 1 day work is 1/24
  jake and paul 1 day's work=1/16+1/24=5/48
  
  jake,paul and hari 1day work=1/8
  
  hari's 1 day work=1/8-5/48=1/48
  
  hari alone can do the work in 48 days
  so ans z a)48
• 9 years agoHelpfull: Yes(0) No(0)
• Hari alone work = 1/8 -(1/16 + 1/24)
  = 1/8 - 5/48
  =1/48
  therefore,
  Hari alone work done = 48 days
• 9 years agoHelpfull: Yes(0) No(1)
• 1/16+1/24+c=1/8
  c=1/8-1/16-1/24
  c=1/48
  so c means hari can dig a wall in 48 days
  
• 9 years agoHelpfull: Yes(0) No(0)
• assume work=1 unit
  jake can dig a well in 16days so, 1/16
  then paul can dig same well in 24days so,1/24
  now three of them can dig the well in 8days so,1/8
  jake + paul + hari = 1/8
  1/16 + 1/24 + 1/hari = 1/8
  1/hari =1/8 - 1/16 - 1/24
  lcm of (8,16,24) is 48
  1/hari = (6-3-2)/48
  1/hari = (6-5)/48
  1/hari = 1/48
  so,hari alone can dig the well in 48 days.
• 6 years agoHelpfull: Yes(0) No(0)
• solution is 48
• 5 years agoHelpfull: Yes(0) No(0)