.construct the number 101102103104………………………149250 obtained by writing the numbers 101,102,……………..149,150 together what is the remainder when this number is divided by 9 a)0 b)8 c)2 d)3

• S=N/2(a1+an)
  =50/2(101+150)
  =6275
  6275/9
  rem=2
• 9 years agoHelpfull: Yes(13) No(1)
• Here add up accordingly: 1*50=50
  0*9+1*10+2*10+3*10+4*10+5=105
  1+2+3+4+5+6+7+8+9=45
  45*5=225
  total=225+105+50=380
  now 380/2
  reminder is 2
  
• 9 years agoHelpfull: Yes(4) No(0)
• should be 2...
• 9 years agoHelpfull: Yes(2) No(0)
• after doing all Calculation we get 380
  hence 380%9 = 2 as rem.
• 9 years agoHelpfull: Yes(2) No(0)
• 0
  150/3
  reminder is 0
• 9 years agoHelpfull: Yes(1) No(8)
• The divisibility rule for 9 is sum of the digits is to be divisible by 9. So
  We calculate separately, sum of the digits in hundreds place, tenths place, and units place.
  Sum of the digits in hundreds place: 1 x 50 = 50
  Sum of the digits in tenths place : 0 x 9 + 1 x 10 + 2 x 10 + 3 x 10 + 4 x 10 + 5 x 1 = 105
  Sum of the digits in units place : (1 + 2 + 3 + ...+ 9) x 5 = 225
  So total = 380
  So remainder = 380 / 9 = 2
• 2 years agoHelpfull: Yes(0) No(0)