a mother her little daughter and her just born infant boy together stood on a weighing machine which shows 74kgs.how much does the daughter weigh if the mother weighs 46kg more than the combined weight of daughter and the infant and the infant weighs 60% less than the daughter a)9 b)11 c)cannot be determined d)10

• daughter weight is x
  infant weight is 60% less than daughter i.e., 0.4x
  
  mother weight is (x+0.4x+46)
  
  total weight = x + 0.4x + (x+0.4X+46) = 74
  solving the eq. x = 10
  option d is correct
• 8 years agoHelpfull: Yes(7) No(2)
• let daughter wgt is x,
  so infant wgt is x-60%of x => x-3x/5 = 2x/5
  mother age is = 46 + x+2x/5 = 46+7x/5
  total age is =>
  46+7x/5 + x+2x/5 = 74
  so x =10
  
• 8 years agoHelpfull: Yes(4) No(1)
• Ans is d)10
• 8 years agoHelpfull: Yes(2) No(1)
• here given weights of mother+daughter+boy=74kgs----eq1
  mother=daughter+boy+46----eq2
  boy=daughter - 60%daughter
  =0.4daughter--eq3
  putting the value eq1 and eq3in eq1
  daughter=10
  
  
• 8 years agoHelpfull: Yes(2) No(1)
• let daughter weight D,mother M and infant I.
  given D+M+I=74;-----------(1)
  now M=D+I+46------(2)
  & I=2/5D-(3)
  substitute this value in (1)
  2D+4D/5=38
  D=10 :)
  
• 8 years agoHelpfull: Yes(2) No(1)
• you are right buddy!
  
• 8 years agoHelpfull: Yes(1) No(1)
• let the wait of mother daughter and infant be M , D , C repectively
  therefore M + D + C = 74 ...... .. (1)
  and M = 46 + C + D........... (2)
  as C is 60% less than D
  => c = 0.4D ......... (3)
  solving above equation we get D = 10.
  
• 8 years agoHelpfull: Yes(0) No(1)