Find the total number of divisors of 1728(including 1 and 1728).

• 1728=2^6*3^3
  no. of divisors = (6+1)*(3+1)=28
  
• 8 years agoHelpfull: Yes(13) No(0)
• 1728= 2^6*3^3
  
  so number of divisors = 7*4=28
• 8 years agoHelpfull: Yes(8) No(0)
• ans: 28
  take lcm of 1728 = 2^6*3^3
  now taking powers 6,3
  then adding 1 to power (6+1)(3+1)=7*4=28
• 8 years agoHelpfull: Yes(4) No(0)
• 1728= (2^6)*(3*3)
  Total no. of divisors= (6+1)*(3+1)
  =>7*4=28
• 8 years agoHelpfull: Yes(2) No(0)
• (2^5)*(3^2)=(5+1)*(2+1)=6*3=18
• 8 years agoHelpfull: Yes(0) No(0)
• 1728-2*2*2*2*2*2*3*3*3
  =(6+1)*(3+1)=28 ans
• 8 years agoHelpfull: Yes(0) No(0)
• Why 1 is added plz explain
• 7 years agoHelpfull: Yes(0) No(0)
• because to find out the factors prime number power +1 is the formula
• 5 years agoHelpfull: Yes(0) No(0)