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Numerical Ability
Number System
Find the total number of divisors of 1728(including 1 and 1728).
Read Solution (Total 8)
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- 1728=2^6*3^3
no. of divisors = (6+1)*(3+1)=28
- 9 years agoHelpfull: Yes(13) No(0)
- 1728= 2^6*3^3
so number of divisors = 7*4=28 - 9 years agoHelpfull: Yes(8) No(0)
- ans: 28
take lcm of 1728 = 2^6*3^3
now taking powers 6,3
then adding 1 to power (6+1)(3+1)=7*4=28 - 9 years agoHelpfull: Yes(4) No(0)
- 1728= (2^6)*(3*3)
Total no. of divisors= (6+1)*(3+1)
=>7*4=28 - 9 years agoHelpfull: Yes(2) No(0)
- (2^5)*(3^2)=(5+1)*(2+1)=6*3=18
- 9 years agoHelpfull: Yes(0) No(0)
- 1728-2*2*2*2*2*2*3*3*3
=(6+1)*(3+1)=28 ans - 9 years agoHelpfull: Yes(0) No(0)
- Why 1 is added plz explain
- 8 years agoHelpfull: Yes(0) No(0)
- because to find out the factors prime number power +1 is the formula
- 6 years agoHelpfull: Yes(0) No(0)
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