TCS
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Numerical Ability
Arithmetic
Apples cost L rupees per kilogram for the first 30 kilograms and Q per kilogram for each additional kilogram. If the price paid for 33 kilograms of Apples is Rs.1167 and for 36 kilograms of apples if Rs.1284, then the cost of the first 10 kgs of apples is:
Read Solution (Total 8)
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- Answer: b
Explanation:
Given that
30L + 3Q = 1167
30L + 6Q = 1284
Solving we get Q = 39, L = 35
So cost of first 10 kgs of apples = 35 × 10 = 350 - 9 years agoHelpfull: Yes(16) No(2)
- Cost of 36 Kg- Cost of 33 Kg=1284-1167
=>cost of 3 Kg (3Q)=117(means 39 Rs. per KG)
=> Cost of 30Kg=1167-117=1050
now Cost of 1 kg= 1050/30
=35 - 9 years agoHelpfull: Yes(5) No(1)
- Given that
30L + 3Q = 1167 ( 33 kgs )
30L + 6Q = 1284 ( 36 kgs )
Solving we get
3Q = 117
Q= 39
thus,L = 35
So cost of first 10 kgs of apples = 35 × 10 = 350 - 9 years agoHelpfull: Yes(4) No(0)
- 30kgs of apples=30L
33kgs of apples=30L+3Q
36 kgs of apples=30L+6Q
1kg of the apple=L=35
10kg of the apples=350 - 9 years agoHelpfull: Yes(0) No(0)
- ans is 350. as explained above
- 9 years agoHelpfull: Yes(0) No(0)
- 36 kg apples cost is Rs 1284 and 33 kg apples cost is Rs 1167. After subtracting these two we get the cost of 3 kg apple i.e. Rs 117. By using this we get the cost of first 30 kg apples which is Rs 1050. so cost of 10 kg apples is Rs 350
- 9 years agoHelpfull: Yes(0) No(0)
- Answer : 350 rs
explaination:
30L + 3Q=1167-----(1)
30L+ 6Q =1284-----(2)
(2)-(1)
3Q=117
Q=39
and l= 35
so, 35*10= 350 rs ans
- 9 years agoHelpfull: Yes(0) No(0)
- price of additional 3 kg is (1284-1167)= 117
then additional1 kg price = 117/3= 39
first 30 kg apple price = (1167-(3*39))=1050
then 10 kg price is =(1050/3)=350/-(ans) - 7 years agoHelpfull: Yes(0) No(0)
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