TCS
Company
Numerical Ability
Algebra
If 1535/1038 = a+1/[b+1/{c+(d+1/e)}]. Find a*b*c*d*e.
Read Solution (Total 14)
-
- by expanding 1535/1038 make form like a+1/[b+1/{c+(d+1/e)}
we get
a=1, b=2,c=11,d=3,e=13/5 - 9 years agoHelpfull: Yes(16) No(18)
- by expanding 1535/1038 make form like a+1/[b+1/{c+(d+1/e)}
=1+(497/1038) now a=1
=1+{1/(1038/497)}
=1+{1/(2+42/497)}
=1+{1/(2+1/(497/42)} now b= 2 similarly expand
c=11 d= 1 e=34/8
finally a*b*b*c*d*e
1*2*11*1*34/8
187/2
- 9 years agoHelpfull: Yes(8) No(5)
- if the above eqn is like 1535/1038 = a+1/[b+1/{c+1/(d+1/e)}]. Find a*b*c*d*e then it can be solved. I think given form is not correct
- 9 years agoHelpfull: Yes(6) No(5)
- @Rahul Rofl... this was the worst comment I had read on this site...
- 9 years agoHelpfull: Yes(6) No(6)
- a=1,b=2,c=11,d=3,e=2.Ans :132
1st 1535/1038=1+497/1038 i.e a=1
2nd 1038/497=2+44/497 i.e b=2
3rd 497/44=11+13/44 i.e c=3
4th 44/13=3+5/13 i.e d=3
5th 13/5=2+3/5 i.e e=2 - 9 years agoHelpfull: Yes(5) No(6)
- Vijay if u do 1038/497 then the ans is 2+44/497 not 2+42/497. And from where u get the value of d & e can u plz explain.
- 9 years agoHelpfull: Yes(3) No(2)
- hi pooja u r looking brilliant , will you please help me in cracking my tcs written test
- 9 years agoHelpfull: Yes(2) No(50)
- yes i m agree with you pooja
- 9 years agoHelpfull: Yes(0) No(2)
- I also in favor of Pooja sow regarding this question.
- 9 years agoHelpfull: Yes(0) No(1)
- Rahul btw its a complement or comment? :p
Pooja u cleared tcs? - 9 years agoHelpfull: Yes(0) No(1)
- a=1, b=2,c=11,d=3,e=13/5
but how we get? explain this. - 8 years agoHelpfull: Yes(0) No(1)
- 132 is the answer
- 8 years agoHelpfull: Yes(0) No(1)
- so what is the exact solution
- 8 years agoHelpfull: Yes(0) No(1)
- Right question is 3^48+3^1996+3^3943+3^3n
so check the difference b/w to power 1996-48=1948.
again check then we will get 3943-1996=1947.
so here we can see that the difference b/w 1st two power and 2nd two power decreased by 1.
so we can write for 3rd power i.e.
3n-3943=1946
n=1963 answer - 5 years agoHelpfull: Yes(0) No(0)
TCS Other Question