2,7,36,4,14,225,6,21,?

• it's three separate sequences. 2, 4, 6.. which are +2 each instance; 7, 14, 21.. which are +7 each instance; and 36, 255, 576.. which are squares +9 each instance. 62 = 36. (6+9=15, so..) 152 = 225, (15+9=24, so..) 242 = 576.
• 9 years agoHelpfull: Yes(37) No(4)
• 2,7,36
  4,14,225
  6,21,?
  
  set of three numbers
  2 4 6 is (differnce between niumbers is 2)
  7 14 21(differnce between niumbers is 7)
  36 225 ?(it is 6^ 2,15^2, is differnce between two number is 9 then 15+9 = 24,24^2 =576)
  ans = 576
• 8 years agoHelpfull: Yes(12) No(3)
• 2,7,(x)2, x+3=2+7=9 x=6
  4,14,(y)2 y+3=14+4=18 y=15
  6,21,(z)2 z+3=21+6=27 z=24 answer=24*24=576
• 9 years agoHelpfull: Yes(3) No(5)
• (2+7-3)^2 = 36
  (4+14-3)^2=225
  (6+21-3)^2=676,
  I think it depends on what choices the question offers. The 576 answer makes sense too.
• 8 years agoHelpfull: Yes(3) No(2)
• hear 36 and 225 are perfect squares of 6 and 15
  and hear 15-6=9
  and so that 15+9= 24
  so next number is 24^2=674
• 8 years agoHelpfull: Yes(3) No(5)
• 
  2, 7, 36, 4, 14, 225, 6, 21, ?
  break in three series
  2, 4, 6 (increments by +2)
  7,14,21 (increments by +7)
  
  36(62),225(152),?
  62, 152 , ? ( increments by +9)
  
  so ans is (15+9)2 = 242 = 576
• 8 years agoHelpfull: Yes(2) No(3)
• 2*2=4, 2*3=6
  7*2=14, 7*3=21
  6^2=36 is even number square
  15^2=225 is odd number square
  20^2=400 is even number square
  answer is 400
  
• 8 years agoHelpfull: Yes(2) No(0)
• group by 3 numbers as
  2 4 6 (result of adding 2)
  7 14 21 (multiple of 7)
  36 225 ? (square of numbers whose difference is 9 starting from 6 i.e 6^2 =36 6+9=15 so 15^2 =225 now 15+9 =24 then 24^2 =576
• 8 years agoHelpfull: Yes(2) No(0)
• .... .... 6*6 ..... ..... 15*15 .... ...(now there must b ) 24*24=576 ans
• 8 years agoHelpfull: Yes(1) No(0)
• 576 = 24*24
• 8 years agoHelpfull: Yes(0) No(0)
• series like this....
  2,4,6.....
  7,14,21....
  here,
  6^2,15^2 difference is 9.
  so,15+9=24^2=576.
• 8 years agoHelpfull: Yes(0) No(0)
• Hello everyone,
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• 8 years agoHelpfull: Yes(0) No(0)