how many integer x satisfies the equation x 2-x-1 x 2 1

Ans must be 4.
Process:
Apply log on both side
(x+2).log(x^2-x-1)=log(1)

so we know log of 1 is 0,So now the eq became
(x+2).log(x^2-x-1) =0
so,suppose x+2=0
.
. . x=-2
if x^2-x-1=0

x=2,-1;
and x=0 when we are putting x =0 in the above question.

Therefore total no. of solution for the the above question is 4.
9 years agoHelpfull: Yes(3) No(0)
Ans is 4
X = 0 , -1 , -2 , 2
9 years agoHelpfull: Yes(1) No(0)
only 2 value will satisfied
9 years agoHelpfull: Yes(0) No(4)
2 will satisfy the equation because let us consider this equation as (X^2-X-1)^X+2=1^X+2 then X^2-X-1=1 and then X=2 will satiisfy the equation (note: 1^x+2=1)
9 years agoHelpfull: Yes(0) No(3)
3 int values will satisfy the equation
x= 0
x= -1
x= 2
9 years agoHelpfull: Yes(0) No(2)
0,-1,1,2,-2
total 5
9 years agoHelpfull: Yes(0) No(6)

how many integer x satisfies the equation (x^2-x-1)^x+2 = 1