x,y,z are positive integers if xy+yz=63, xz+yz=40. what is the value of x+y+z?

• question is : x,y,z are positive integers if xy+yz=63, xz+yz=23. Find value of x+y+z?
  x=20, y=3, z=1 => x+y+z=24
  
• 8 years agoHelpfull: Yes(5) No(2)
• y(x+z)=63 z(x+y)=23
  3.21=63 1.23=23
  y=3, x+z=21 =>1 z=1, x+y=23 =>2
  put z=1 in eq 1 put x=20 in eq 2
  x+1=21=>x=20 20+y=23=> y=3
  => x+y+z=20+3+1=24
• 8 years agoHelpfull: Yes(3) No(10)
• ITS WRONG...I THINK
  
• 8 years agoHelpfull: Yes(3) No(2)
• Question is wrong.
  x,y,z are positive integers if x(y+z)=49, y(z+x)=40, z(y+x)=33. what is the value of x+y+z?
  X(y+z) = 49 = 7*7
  Y(z+x) = 40 = 4*10
  Z(y+x) = 33 = 3*11
  Therefore, x= 7, y= 4, z= 3
  Therefore, x+y+z= 7+4+3 = 14
  
• 8 years agoHelpfull: Yes(3) No(0)
• Question was: x,y,z are positive integers if x(y+z)=63, y(z+x)=40, z(y+x)=33. what is the value of x+y+z?
  
• 8 years agoHelpfull: Yes(2) No(0)
• S@ch!n
  xy+yz = 63
  y(x+y) = 63 so that y =21 , 3 and (x+y) = 3 , 21
  but
  xz+yz = 40
  z(x+y) = 40 so that z = 20 ,8 , 5 , 1 ,40 and (x+y) = 2 , 5 , 8 , 40 , 1
  so that only one case is possible
  x = 20
  y = 3
  z =1
  x+y+z = 24 Ans
• 8 years agoHelpfull: Yes(1) No(1)
• 24 is the right ans
• 8 years agoHelpfull: Yes(0) No(0)