What is the last two digits of the given number having 200 digits?
123412344123444123444412.....
options-a)12
b)23
c)34
d)41
e)44

• 1st group 1234 number of digit 4
  2nd group 12344 number of digit 5
  3rd group 1234444 number of digit 6
  so at the end of each group there will be series of 4s.
  So the answer is 44 (option e)
  
• 8 years agoHelpfull: Yes(7) No(5)
• e) 44
  iz the ryt answer !
• 8 years agoHelpfull: Yes(2) No(1)
• answer will be e)44
• 8 years agoHelpfull: Yes(1) No(1)
• series is n+3.
  first term will have =4
  so n+3=200
  n=194
  so it will end with 44
• 8 years agoHelpfull: Yes(1) No(4)
• 44 is correct ans
• 8 years agoHelpfull: Yes(1) No(0)
• correct answer is 44
• 8 years agoHelpfull: Yes(1) No(0)
• d) 41 is correct
• 7 years agoHelpfull: Yes(1) No(0)
• the given series is 1234 12344 123444.......
  
  So the number of digits in each term are 4, 5, 6, ... or (3 + 1), (3+ 2), (3 +3),......upto nth terms are=3n [n(n 1)/2]
  
  
  
  so 3n [n(n 1)/2]>=200
  
  For n = 16, We get 184 in the left hand side. So after 16 terms the number of digits equal to 184. And 16 them contains 16 3 = 19 digits.
  
  Now 17 term contains 20 digits and 123444......4(17times)... last two digits are 55.
• 6 years agoHelpfull: Yes(1) No(0)
• 44 is correct answer.
• 8 years agoHelpfull: Yes(0) No(0)
• 44 last one
• 8 years agoHelpfull: Yes(0) No(0)
• every time the value of 4 is incresing by 1 unit then
  in last group 183+3=186
  186+17 times 44 == so the answer is 44
• 6 years agoHelpfull: Yes(0) No(0)