a spider web consists of 3 concurrent lines forming radial support for 20 concentric regular hexagon .the hexagon vertices are 5mm from their immidiate neighbour. if the innermost hexagon has a side length 3mm how many meters is the length of the entire web including the 3 diagonals ?

• the correct answer is 6.648 meters
  6060 is correct from the below solution but the sum length of diagonals is 6*98=588
  so 6.060+0.588=6.648 meters
• 9 years agoHelpfull: Yes(15) No(1)
• for perimeter of all hexagon =6*(3+8+13+...........20th term.)
  sum will be 6060 mm
  and for length of one diagonal find 20th term=98
  
  so total length =6060+294=6354 mm=6.354 m
  if i made any mistake pl correct me ......
• 9 years agoHelpfull: Yes(5) No(3)
• 20*(3+98)/2 =1010
  1010*6= 6060 (hexa =6)
  series last is 98 so bcz 6line from the center of hexa.
  98*6 =588
  
  so entire web length = sum of perimeter of all hexa + the length from centre to last hexa
  = 6060 + 588
  = 6648 ( 6.648 meter)
  
  6.648 meter is ri8
  
• 9 years agoHelpfull: Yes(3) No(0)
• side of innermost hexagon = 3mm
  side of next hexagon = 8mm
  it goes on as series 3,8,13... 20th terms
  total length of smallest hexagon = 6 * 3= 18mm
  next hexagon length = 6 * 8= 48mm
  
  sum of all hexagon sides = 20/2 * (2*18 + 19 * 30) = 6060mm
  sum of length 3 diagonal = 3*(sum of the series (3,8,13,...98)
  3 * 1010 = 3030
  
  Total length of the spider web = 6060 + 3030 = 9090mm
  
• 9 years agoHelpfull: Yes(2) No(5)
• wats the correct answer
• 9 years agoHelpfull: Yes(0) No(0)
• either 7.5 or 6.04
• 9 years agoHelpfull: Yes(0) No(0)
• @piyush in question it is saying only three diagonals but added extra three why?
• 9 years agoHelpfull: Yes(0) No(0)
• 6.060+0.285=6.285 meters
  because 3 diagonals only...And the diagonals are starting from the vertices of first hexagon i.e. the
  inner most one.
• 3 years agoHelpfull: Yes(0) No(0)