xy+yz=63
xz+yz=23
find x+y+z unable to recall the options

• simple question
  take z as common term in second equation
  ie z(x+y)=23
  now as 23 is prime no therefore its factors must be 1 and 23.
  now as x,y,z is integer no therefore z= 1 as sum of two integer cannot be equal to 1.
  => z= 1 and x + y = 23
  therefore x+y+z = 1 + 23 = 24.
• 9 years agoHelpfull: Yes(101) No(1)
• 23 is a prime number, so that second eqn has less uncertainty.
  x+y>2 and 23 is a Prime leads to z=1.
  Hence x+y=23 =>y=23-x....(2) putting this eqn in first equation.
  
  (23-x)(x+1)=63
  x^2-22x+40=0
  (x-2)(x-20)=0
  therefore x1=2 , x2=20
  y1=21 , y2=3
  z=1
  x+y+z=(2+21+1)=24 or x+y+z=(20+3+1)=24
  
  therefore 24 is the answer.
• 9 years agoHelpfull: Yes(11) No(0)
• Great Answer @Binod Kumar Short n sweet...
  
• 8 years agoHelpfull: Yes(3) No(0)