triangle ABC is an isosceles triangle. if AB changed to 3AB and AC changed to 3AC without changing the measure of angle A. what is the change in area

• AB and AC are adjecent sides of trianlge ABC have common angle A.
  we know area of any trianlge = product of two adjecent side * SIN(angle bet them)
  i.e area = AB*AC*SIN(A)
  hence new area = (3AB)*(3AC)*SIN(A)
  = 9 times old area
• 9 years agoHelpfull: Yes(43) No(0)
• It is an isosceles triangle.Therefore, 3AB=3AC and angle is same.
  Then, AB:AC:BC:h = 3AB:3AC:3BC:3h where,h is height [property of isocl. trngl]
  area of any triangle = 1/2 * base * height
  Now,
  area of small trngl : area of large triangle
  1/2 *BC*h : 1/2*3BC*3h [1/2 cancels 1/2 and BC & h cancels BC & h]
  1:9
  Change in area=900%
  
• 9 years agoHelpfull: Yes(3) No(4)
• area of isoceles triangle=AB/4( (4AC^2-AB^2)^1/2)
  so ans is = 3 time of old area
• 9 years agoHelpfull: Yes(1) No(7)
• AB->3AB & AC->3AC
  area2/area1=3*3/1*1=9times
• 8 years agoHelpfull: Yes(1) No(0)
• 9 times is correct ans
• 8 years agoHelpfull: Yes(1) No(2)