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Permutation and Combination
if a die has 1 6 and 3 4 and 2 5 opposite each other how many such dies can be made
Read Solution (Total 12)
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- ans 12
if one face have 1,3,2, then the crossponding face will be occupied by respective pair i.e (6,4,5).
so there r 3 place and we have 3 place soit can be arranged in 3! way i.e 6 way and every pair will be suffled in 2 way so ans will be6*2=12. - 9 years agoHelpfull: Yes(23) No(2)
- Ans::24 ways
if the dice shows 6 on top then 1 will be at the bottom.
so the remaining 3,4 and 2,5 can be plotted in 4 ways so four different dies possible
if 1 is placed on the top then again 4 ways
4*2+4*2+4*2=24 ways - 9 years agoHelpfull: Yes(4) No(6)
- 12
there are 3 pairs : (1,6),(3,4),(2,5)
and each pair has 2 sides
so, 3*2*1*2 = 12 - 9 years agoHelpfull: Yes(4) No(4)
2!+2!+2!=6
all can be arranged in 3! ways
hence 36
- 8 years agoHelpfull: Yes(2) No(1)
- 3!*2*2*2=48
- 8 years agoHelpfull: Yes(2) No(0)
- whats the correct ans
- 8 years agoHelpfull: Yes(2) No(0)
- permutation and combination
- 8 years agoHelpfull: Yes(1) No(1)
- Ans: 8
Taking 1 at one of its faces, the other possibilities for other numbers 2,3,4,5 is 4.
Now interchanging 1 and 6 (2 ways), we will have 4 more possibilities.
Hence, total number if ways: 4*2=8 - 8 years agoHelpfull: Yes(1) No(2)
- Let's take a blank die which has faces a,b,c,d,e,f
(a,b),(c,d),(e,f) are opposite pair of sides
(1,6),(3,4),(2,5) are 3 possible opposite side sets required
These three can be arranged in above blank cube in 3*2 = 6 ways
Each of these pairs can be arranged in 2 ways (1,6) or (6,1).
Therefore Total number of dice possible = 6*2 = 12 - 6 years agoHelpfull: Yes(1) No(0)
- if take 1 and 6 as fixed then total 8 posiblities of (3,4) and (2,5)
then alter 1 and 6 then again 8 posoblities
same for (3,4) and (2,5)
total 48 posiblities but here some 8 posoblities is repeated so answer is:40 - 8 years agoHelpfull: Yes(0) No(1)
- Let us assume their r 2 configurations at a vertice
A. and. A
B. C. C. B
If we interchange A and B in the second configuration then it becomes the first configuration
This means two possible basic arrangements of the the 3 sets at a vertice
Now, 1_6 ,3_4, 5_2. Can interchange.
This gives total ways as 2*2*2*2 - 8 years agoHelpfull: Yes(0) No(1)
- 8 ways = 2*2*2
1 6 1 6 1 6 1 6
3 4 3 4 4 3 4 3
2 5 5 2 2 5 5 2
6 1 6 1 6 1 6 1
3 4 4 3 4 3 3 4
2 5 2 5 5 2 5 2 - 6 years agoHelpfull: Yes(0) No(0)
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