a series 1234123441234441234444.....n what is the value on 200th position..??

• 1234 => 4 times
  12344 => 5 times
  123444 => 6 times
  .
  .
  .
  4 + 5 + 6 + ...n < 200
  n(n+1)/2 - 6 = 200
  So n = 19
  
  i.e. 4+5+6+...19 = 184
  
  After the 184th term,the sequence has 20 terms
  12344444444444444444 = 20 terms
  => 200th term = 4
• 9 years agoHelpfull: Yes(33) No(10)
• Congrats to all those
  who are selected and i am also selected!!!!!!!!!!!!!!!!!!!!
• 9 years agoHelpfull: Yes(13) No(8)
• @ vinay y did u subtract 6 frm the sum.. can u tell me..
• 9 years agoHelpfull: Yes(8) No(1)
• ShaikanSari , vinay subtracted 6 because 1+2+3 = 6 and it must be subtracted from the series , as the first no. is 1234 i e consisting 4 terms in it
• 9 years agoHelpfull: Yes(5) No(1)
• if you will add from 4 +5+6+.....+19=184, now for it will start from 185 as 1234444 upto to 204 place
  so @ 200 place A is the answer [plz correct if wrong ]
• 9 years agoHelpfull: Yes(2) No(5)
• i didn't understand what is the 200th position?
• 7 years agoHelpfull: Yes(2) No(0)
• *4 is the answer
• 9 years agoHelpfull: Yes(0) No(2)
• 1234, 12344, 123444, 1234444, ....
  4, 5, 6, ... or (3 + 1), (3 + 2), (3 + 3), .....n = 3 n+n(n+1)/2
  3 n +n(n+1)/2
• 7 years agoHelpfull: Yes(0) No(0)