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if avaerage of five student ages is 14. what will the average age of these student after 5 years?
Read Solution (Total 20)
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- (a+b+c+d+e+f)/5=14
a+b+c+d+e+f=70------>1
(a+5+b+5+c+5+d+5+e+5+f+5)/5
(a+b+c+d+e+f+25)/5 substitute equation 1
(70+25)/5
ans=19
- 9 years agoHelpfull: Yes(17) No(0)
- Total age = 14* 5 = 70
age of 5 student after 5 yrs = 70 + (5*5) = 95
Avg = 95/ 5 = 19 - 9 years agoHelpfull: Yes(11) No(1)
- it will be 14+5=19 .Because in every year their age is increase by one...
- 8 years agoHelpfull: Yes(5) No(0)
- 15
5 students avg=14
sum =14*5=70
after 5 years sum=75
avg=75/5=15 - 9 years agoHelpfull: Yes(1) No(3)
- 19.
first total sum of ages=14*5=70
next total age after 5 years be 70+25=95
average of 5 students be 95/5=19 - 9 years agoHelpfull: Yes(0) No(0)
- a+b+c+d+e=14*5=70
again ,after five yr average age=a+b+c+d+e+25/5=70+25/5=19 - 9 years agoHelpfull: Yes(0) No(0)
- 5*5=25...25/5=5...i.e 5 students 5 years avg becomes simply '5' so 14+5=19.
- 9 years agoHelpfull: Yes(0) No(0)
- X5/5=14
x5+5(5)/5
14+5
19 - 9 years agoHelpfull: Yes(0) No(0)
- 19 because x5/5=14, we get x5=70 after 5 years we get x5+25/5 =19
- 9 years agoHelpfull: Yes(0) No(0)
- let the sum of 5 students is x
then x/5=14
x=70
after 5 years the sum will be x+25(5*5)
then avg=x+25/5
avg=95
- 9 years agoHelpfull: Yes(0) No(0)
- avg=95/5
avg=19 - 9 years agoHelpfull: Yes(0) No(0)
- Correct @Nidhi
- 8 years agoHelpfull: Yes(0) No(0)
- a+b+c+d+e+f/5=14--------(i)
after 5 years
a+5+b+5+c+5+d+5+e+5/5=unknown
a+b+c+d+e+f+25/5=unknown
a+b+c+d+e+f/5+25/5=unknown
14+5=19=unknown - 8 years agoHelpfull: Yes(0) No(0)
- after 5 yrs also it is 14 only
- 8 years agoHelpfull: Yes(0) No(3)
- avg =sum of terms/no of terms;sum =?,no of terms=5;avg=14;
sum of terms=a+b+c+d+e;
a+b+c+d+e/5=14;a+b+c+d+e=70;
after 5yrs;-
a+5+b+5+c+5+d+5+e+5=70;
a+b+c+d+e=45;
avg of five students after 5 yrs is 45/5=9 - 8 years agoHelpfull: Yes(0) No(7)
- Avg of 5 students = 14
In 5 years age of each student would be increased by 5 years
So, average would also be increased by 5. - 7 years agoHelpfull: Yes(0) No(1)
- 19 perfect.
- 7 years agoHelpfull: Yes(0) No(1)
- (14*5+5*5)/5=19
- 7 years agoHelpfull: Yes(0) No(1)
- 19(a+b+c+d+e+f)/5=14
a+b+c+d+e+f=70------>1
(a+5+b+5+c+5+d+5+e+5+f+5)/5
(a+b+c+d+e+f+25)/5 substitute equation 1
(70+25)/5
ans=19 - 6 years agoHelpfull: Yes(0) No(0)
- 39
correct ans 19
if a perticular no is added or substracted from each no then this no will added or substracted from average value - 6 years agoHelpfull: Yes(0) No(0)
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