Elitmus
Exam
Numerical Ability
Age Problem
How many 3 digits number are there which sum of digits is equal to 16.
Read Solution (Total 12)
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- 100-200=4;
200-300=5;
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700-800=10;
800-900=9;
900-999=8;
Total= 66 - 9 years agoHelpfull: Yes(16) No(0)
- nos end with 9=7
nos end with 8=8
nos end with 7=9
nos end with 6=9
nos end with 5=8
nos end with 4=7
nos end with 3=6
nos end with 2=5
nos end with 1=4
nos end with 0=3
total = 66
- 9 years agoHelpfull: Yes(9) No(0)
- Combination of numbers
9 7 0 = 4
9 6 1 = 6
9 5 2 = 6
9 4 3 = 6
8 8 0 = 2
8 7 1 = 6
8 6 2 = 6
8 5 3 = 6
8 4 4 = 3
7 7 2 = 3
7 6 3 = 6
7 5 4 = 6
6 6 4 = 3
6 5 5 = 3
Total = 66
- 9 years agoHelpfull: Yes(5) No(2)
- The correct ans. is 135
- 9 years agoHelpfull: Yes(2) No(5)
- 66
- 9 years agoHelpfull: Yes(1) No(1)
- 66
- 9 years agoHelpfull: Yes(1) No(1)
- https://en.wikipedia.org/wiki/List_of_perfect_numbers
- 9 years agoHelpfull: Yes(1) No(4)
- let me simplify this for u guys..first exclude the age of youngest one..i,e 6*30 + 23(remaining) -42(reducing the age of remaining 6 person) we will get 161(sum of ages of other 6 people when the young one was born)
161/6 =26.8 is the average of other 6 persons when the young one was born!!
- 9 years agoHelpfull: Yes(1) No(0)
- Use permutation concept
(556)=3!/2! =3 [because 2 no,s are common] [556,655,565]
(574)=3!=6 [574,547,475,457,754,745]
Similarly,
(583)=3!=6
(592)=3!=6
(664)=3!/2!=3
(673)=3!=6
(682)=3!=6
(691)=3!=6
(772)=3!/2!=3
(781)=3!=6
(790)=4 [because 079 and 097 are not 3 digit numbers)
Similarly,
880,808 =2
Total=57 - 9 years agoHelpfull: Yes(0) No(3)
- 66 is correct answer.
- 9 years agoHelpfull: Yes(0) No(1)
- First number =169
second number =178
Third number =187
last number=970
A.P. With d=9
an = a +(n-1).d gives n=90
so its 90. Correct . - 9 years agoHelpfull: Yes(0) No(3)
- 84 is the answr
- 9 years agoHelpfull: Yes(0) No(1)
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