The word HIDING conceals a six digit prime number. Each district letter represents a single digit. H,IAnd D are prime,and consecutive letter pairs HI,DI,andNG are two digit primes all permutations of H and two I's are prime,while HIH is divisible by (2D+1) if N=2^I find H+I+D+I+N-G

• 735389 is the six digit prime number. H+I+D+I+N+G = 35
• 9 years agoHelpfull: Yes(6) No(3)
• 735389 will give 17..but i hardly remember they had given 17...the options were 19,23,21,13
• 9 years agoHelpfull: Yes(3) No(3)
• 1 is nt prime@priyanka misra
• 9 years agoHelpfull: Yes(2) No(0)
• Given HIDING is a prime number
  Now single digit prime numbers are 2,3,5 and 7
  Now two digit numbers with each digit being a prime number are 23,37,53 and 73.
  Since DI and HI has last digit same, so 37 is eliminated.
  Now that gives us I as 3
  NG is a prime number with N as 2. So G must be 9
  That gives us number as H3D329
  So now H and D will be from 7 and 5.
  Given HIH is divisible by (2D+1)
  so either 737 / 11 = 0 or 535/15 = 0
  That gives H as 7 and D as 5
  
  So, H+I+D+I+N-G = 7+3+5+3+2-9 = 11
• 8 years agoHelpfull: Yes(2) No(2)
• Guys it should be
  531387
  as 5*3*5 is divisible by (2*1+1)
  H+I+D+I+N-G=13
• 9 years agoHelpfull: Yes(1) No(5)
• 735323.....ans is 23
• 9 years agoHelpfull: Yes(1) No(0)
• 735323.....ans is 23
• 9 years agoHelpfull: Yes(1) No(0)
• 735323.....ans is 23
• 9 years agoHelpfull: Yes(0) No(0)
• 735323.....ans is 23
• 9 years agoHelpfull: Yes(0) No(0)
• 735323.....ans is 23
• 9 years agoHelpfull: Yes(0) No(0)
• HIDING = 532389
  
  H+I+D+I+N+G = 30
• 8 years agoHelpfull: Yes(0) No(0)
• @shivam 9 is not a prime no.
• 8 years agoHelpfull: Yes(0) No(0)
• i can't find this answer
• 6 years agoHelpfull: Yes(0) No(0)
• Given HIDING is a prime number
  Now single digit prime numbers are 2,3,5 and 7
  Now two digit numbers with each digit being a prime number are 23,37,53 and 73.
  Since DI and HI has last digit same, so 37 is eliminated.
  Now that gives us I as 3
  NG is a prime number with N as 2. So G must be 9
  That gives us number as H3D329
  So now H and D will be from 7 and 5.
  Given HIH is divisible by (2D+1)
  so either 737 / 11 = 0 or 535/15 = 0
  That gives H as 7 and D as 5
  
  So, H+I+D+I+N-G = 7+3+5+3+2-9 = 11
• 4 years agoHelpfull: Yes(0) No(0)