Capgemini
Company
Numerical Ability
Time Distance and Speed
Two trains whose respective lengths are 240 m and 360 m cross each other in 30 seconds when they are moving in opposite directions and in 1 minute 40 seconds when they are moving in the same direction. What is the speed of the faster train (kmph)
a. 39.2 b. 36.6 c. 46.8 d. 33.33 e. 49.2
Read Solution (Total 6)
-
- Given that L1=240 and L2=360
so we know that t=s/v, then 30=240+360/v1+v2, =>v1+v2=20.......(1)
and v1-v2=600/100=6.....(2)
after solving the both equations we get
v1=13 and v2=7
Now we have to convert 13*18/5=46.8
(c.) 46.8 is correct answer.
- 9 years agoHelpfull: Yes(26) No(1)
- 240+360/x+y=30 here x &y are speeds of 2 trains 600/30=x+y I.e x+y =20 we add their speeds bcoz dey r moving in opposite direction similarly 600/x-y=100sec by solving we get x & y values and speed of faster train is 46.8
- 9 years agoHelpfull: Yes(3) No(0)
- 46.8 will be the ans as s=d/t here s1+s2=240+360/30, s1-s2=6 and
s1=7,s2=13,we get faster train speed as 13*18/5=46.8 - 9 years agoHelpfull: Yes(1) No(0)
- let s1, s2 be the speed of the two trains
opposite direction 30=240+360/s1+s2
gives s1+s2 = 20
same direction 100=240+360/s1-s2
gives s1-s2=6
solving two equations
s1=13m and s2=7m
13*18/5 = 46.8kmph - 7 years agoHelpfull: Yes(1) No(0)
- S1+S2=20
S1-S2=6
S1=13
S2=7
S1=(13*18)/5=46.8kmph - 8 years agoHelpfull: Yes(0) No(0)
- given that L1=240 and L2=360
consider the speed of first train is x and the speed of another train is y
accourding to concept of average speed
avrage time=total distace / tota speeed
30=600/x+y(when the train is in opposite direction)...(1)
100=600/x-y(when the train is in same direction )...(2)
now solv equation 1 and 2 and enjoy the answer...
- 8 years agoHelpfull: Yes(0) No(0)
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