Two trains whose respective lengths are 240 m and 360 m cross each other in 30 seconds when they are moving in opposite directions and in 1 minute 40 seconds when they are moving in the same direction. What is the speed of the faster train (kmph)
a. 39.2 b. 36.6 c. 46.8 d. 33.33 e. 49.2

• Given that L1=240 and L2=360
  so we know that t=s/v, then 30=240+360/v1+v2, =>v1+v2=20.......(1)
  and v1-v2=600/100=6.....(2)
  after solving the both equations we get
  v1=13 and v2=7
  Now we have to convert 13*18/5=46.8
  (c.) 46.8 is correct answer.
  
• 8 years agoHelpfull: Yes(26) No(1)
• 240+360/x+y=30 here x &y are speeds of 2 trains 600/30=x+y I.e x+y =20 we add their speeds bcoz dey r moving in opposite direction similarly 600/x-y=100sec by solving we get x & y values and speed of faster train is 46.8
• 8 years agoHelpfull: Yes(3) No(0)
• 46.8 will be the ans as s=d/t here s1+s2=240+360/30, s1-s2=6 and
  s1=7,s2=13,we get faster train speed as 13*18/5=46.8
• 8 years agoHelpfull: Yes(1) No(0)
• let s1, s2 be the speed of the two trains
  opposite direction 30=240+360/s1+s2
  gives s1+s2 = 20
  same direction 100=240+360/s1-s2
  gives s1-s2=6
  solving two equations
  s1=13m and s2=7m
  13*18/5 = 46.8kmph
• 6 years agoHelpfull: Yes(1) No(0)
• S1+S2=20
  S1-S2=6
  S1=13
  S2=7
  S1=(13*18)/5=46.8kmph
• 7 years agoHelpfull: Yes(0) No(0)
• given that L1=240 and L2=360
  consider the speed of first train is x and the speed of another train is y
  accourding to concept of average speed
  avrage time=total distace / tota speeed
  30=600/x+y(when the train is in opposite direction)...(1)
  100=600/x-y(when the train is in same direction )...(2)
  now solv equation 1 and 2 and enjoy the answer...
  
  
  
  
  
• 7 years agoHelpfull: Yes(0) No(0)