a factory produces 1 defective bulb out of 10 bulbs a yr. if it produces 870 bulbs a yr, how many defective bulbs are produced?

• 87
  10 out of 1 is defective
  20 out of 2 is defective
  100 out of 10 is defective
  and so on
  800 out of 80 is defective
  70 out of 7 is defective
  80+7=87
• 9 years agoHelpfull: Yes(18) No(0)
• acc to questn 1/10 is defective to get 870 multiplying numerator n denominator by 87 we get
  1*87/10*87= 87/870 . Hence , 87 r defctive out of 870.
  
• 9 years agoHelpfull: Yes(2) No(0)
• ABSOLUTELY ANSWER IS 870/10
  =87
• 8 years agoHelpfull: Yes(1) No(0)
• for 10 bulbs 1 defective
  for 870 means 87*10==1*87=87defectives bulbs
• 9 years agoHelpfull: Yes(0) No(0)
• 87
  10% is loss. so, 10% of 870.
• 9 years agoHelpfull: Yes(0) No(0)
• 87
  out of 10 bulbs 1 bulb is defective
  hence out of 870 bulbs 87 bulbs are defective
• 9 years agoHelpfull: Yes(0) No(0)
• 10 bulbs= 1 def
  870 bulbs= x def
  cross multiply
  X*10=870
  X=87
• 9 years agoHelpfull: Yes(0) No(0)
• 10 bulbs --- 1def
  870 bulbs --- X
  
  then 10*X = 870 * 1
  X = 87
• 8 years agoHelpfull: Yes(0) No(0)
• if 1 bulb is defective out of 10 bulb
  then,defective bulb out of 1 bulb=1/10
  so,defective bulb out of 870 bulb=1/10*870=87
• 8 years agoHelpfull: Yes(0) No(0)