A sum of Rs. 900 amounts to Rs. 950 in 3 years at simple interest. If the interest rate is increased by 4%, it would amount to how much?

• P=900
  T=3
  SI= 900-950=50
  R= 50 x 100/900 x 3 = 50/27
  now rate is increased by 4% and we have rate % 50/27 ....so new rate% is =50/27 + 4= 158/27
  SI = (900 x 3 x 158)/ 100 x 27 = 158
  since Si 158 and P =900 so new amount is .......900+158= 1058 ans
  ans 1058
• 9 years agoHelpfull: Yes(58) No(2)
• s.i=950-900=50, p=900 , t=3
  r=50*100/(900*3)=1.85
  new rate =1.85 +4=5.85
  new s.i=(900*5.85*3)/100=157.95
  new amount=1057.95
• 9 years agoHelpfull: Yes(6) No(6)
• p=900
  (si)3+p =950
  (si)3=50
  A=p(1+TR/100)+si
  A=900(1+3*4/100)+50
  =1058
• 8 years agoHelpfull: Yes(4) No(1)
• 50=3*900*r/100
  r=50/27
  si=900*(50/27)*(104/100)*3/100
  si=52
  sum = 900+52=952
• 8 years agoHelpfull: Yes(3) No(4)
• s.i=p*t*r/100
  r=50*100/(900*3)
  r=50/27
  rate is incresed by 4%
  r=(50/27)+4*(50/27)
  r=250/27
  s.i=900*3*(250/27)/100
  s.i=250
  amount=900+250
  =1150
• 9 years agoHelpfull: Yes(1) No(8)
• s.i=950-900=50 ,p=900 t=3
  r=50*100/(900*3)=2.08
  new rate=2.08+4=6.08
  new s.i=900*6.08*3/100=164.12
  new amount=900+164.12=1064.12
  
• 9 years agoHelpfull: Yes(0) No(8)
• Si=950-900
  50=900×3×r/100
  r=5.85
  New rate=5.85+4=9.85
  Si=900×9.85×3/100=266
  Amount =900+266=1166
• 9 years agoHelpfull: Yes(0) No(6)
• ANS :: 8
  
  
  2^1 = 2
  2^2 = 4
  2^3 = 8
  2^4 = 16
  2^5 = 32
  2^6 = 64
  2^7 = 128
  2^8 = 256
  ....
  last digits are {2,4,8,6...,2,4,8,6} i.e.,for every 4 sets the last digits are repeated so 12*4+3 digits so 2^51 has last digit is "8".
• 7 years agoHelpfull: Yes(0) No(0)
• SI = (P x R x T)/100
  SI = 950-900 = 50
  SI = (900 x R x 3)/100
  50 = 9 x 3 x R
  R = 50/27
  
  4% increment in rate, So new rate = 50/27 x 104/100 = 2%
  Amount = P + SI
  = 900 + (900 x 2 x 3)/100
  = 900 + 54
  = 954
• 6 years agoHelpfull: Yes(0) No(3)
• interest = 950-900= rs 50
  rate= (50*100)/(3*900) = 50/27
  
  rate is increased by 4% = (50/27)+4=158/27
  
  new interest = (900*158*3)/(100*27) = rs 158
  
  so amount =900+158= rs 1058
• 6 years agoHelpfull: Yes(0) No(0)
• P=900
  T=3
  SI= 900-950=50
  R= 50 x 100/900 x 3 = 50/27
  now rate is increased by 4% and we have rate % 50/27 ....so new rate% is =50/27 + 4= 158/27
  SI = (900 x 3 x 158)/ 100 x 27 = 158
  since Si 158 and P =900 so new amount is .......900+158= 1058 ans
  ans 1058
• 6 years agoHelpfull: Yes(0) No(0)
• Given: Principal = Rs.900
  
  Time = 3 years
  
  Amount = Rs.950
  
  We know that, Simple Interest = Amount - Principal
  
  = Rs.950 - Rs.900
  
  S.I. =Rs.50
  
  By using: Simple Interest = (Principal*Rate*Time)/100
  
  We have: 50=(900*Rate*3)/100
  
  => Rate = 50/27% per annum
  
  Now, if rate is increased by 4%, then
  
  New rate, R' = 50/27 + 4 = 158/27%
  
  New SI = (P*R'*T)/100
  
  =(900*(158/27)*3)/100
  
  = Rs.158
  
  New amount will be = Principal + New SI
  
  = Rs.900 + Rs.158
  
  = Rs.1058
• 5 years agoHelpfull: Yes(0) No(0)
• A=P(1+rt) where rate of interest=r/100
  from the first line we get
  950=900(1+(3*r)/100)
  r= 50/27
  now interest rate is increased by 4%
  so r= 50/27 + 4
  =158/27
  from the first equation we get =900 * (1 + (( 158 * 3 ) / ( 27 * 100 )))
  =1058
• 5 years agoHelpfull: Yes(0) No(0)