Capgemini
Company
Numerical Ability
Simple & Compound Interest
A sum of Rs. 900 amounts to Rs. 950 in 3 years at simple interest. If the interest rate is increased by 4%, it would amount to how much?
Read Solution (Total 13)
-
- P=900
T=3
SI= 900-950=50
R= 50 x 100/900 x 3 = 50/27
now rate is increased by 4% and we have rate % 50/27 ....so new rate% is =50/27 + 4= 158/27
SI = (900 x 3 x 158)/ 100 x 27 = 158
since Si 158 and P =900 so new amount is .......900+158= 1058 ans
ans 1058 - 8 years agoHelpfull: Yes(58) No(2)
- s.i=950-900=50, p=900 , t=3
r=50*100/(900*3)=1.85
new rate =1.85 +4=5.85
new s.i=(900*5.85*3)/100=157.95
new amount=1057.95 - 9 years agoHelpfull: Yes(6) No(6)
- p=900
(si)3+p =950
(si)3=50
A=p(1+TR/100)+si
A=900(1+3*4/100)+50
=1058 - 7 years agoHelpfull: Yes(4) No(1)
- 50=3*900*r/100
r=50/27
si=900*(50/27)*(104/100)*3/100
si=52
sum = 900+52=952 - 8 years agoHelpfull: Yes(3) No(4)
- s.i=p*t*r/100
r=50*100/(900*3)
r=50/27
rate is incresed by 4%
r=(50/27)+4*(50/27)
r=250/27
s.i=900*3*(250/27)/100
s.i=250
amount=900+250
=1150 - 8 years agoHelpfull: Yes(1) No(8)
- s.i=950-900=50 ,p=900 t=3
r=50*100/(900*3)=2.08
new rate=2.08+4=6.08
new s.i=900*6.08*3/100=164.12
new amount=900+164.12=1064.12
- 9 years agoHelpfull: Yes(0) No(8)
- Si=950-900
50=900×3×r/100
r=5.85
New rate=5.85+4=9.85
Si=900×9.85×3/100=266
Amount =900+266=1166 - 9 years agoHelpfull: Yes(0) No(6)
- ANS :: 8
2^1 = 2
2^2 = 4
2^3 = 8
2^4 = 16
2^5 = 32
2^6 = 64
2^7 = 128
2^8 = 256
....
last digits are {2,4,8,6...,2,4,8,6} i.e.,for every 4 sets the last digits are repeated so 12*4+3 digits so 2^51 has last digit is "8". - 7 years agoHelpfull: Yes(0) No(0)
- SI = (P x R x T)/100
SI = 950-900 = 50
SI = (900 x R x 3)/100
50 = 9 x 3 x R
R = 50/27
4% increment in rate, So new rate = 50/27 x 104/100 = 2%
Amount = P + SI
= 900 + (900 x 2 x 3)/100
= 900 + 54
= 954 - 6 years agoHelpfull: Yes(0) No(3)
- interest = 950-900= rs 50
rate= (50*100)/(3*900) = 50/27
rate is increased by 4% = (50/27)+4=158/27
new interest = (900*158*3)/(100*27) = rs 158
so amount =900+158= rs 1058 - 6 years agoHelpfull: Yes(0) No(0)
- P=900
T=3
SI= 900-950=50
R= 50 x 100/900 x 3 = 50/27
now rate is increased by 4% and we have rate % 50/27 ....so new rate% is =50/27 + 4= 158/27
SI = (900 x 3 x 158)/ 100 x 27 = 158
since Si 158 and P =900 so new amount is .......900+158= 1058 ans
ans 1058 - 6 years agoHelpfull: Yes(0) No(0)
- Given: Principal = Rs.900
Time = 3 years
Amount = Rs.950
We know that, Simple Interest = Amount - Principal
= Rs.950 - Rs.900
S.I. =Rs.50
By using: Simple Interest = (Principal*Rate*Time)/100
We have: 50=(900*Rate*3)/100
=> Rate = 50/27% per annum
Now, if rate is increased by 4%, then
New rate, R' = 50/27 + 4 = 158/27%
New SI = (P*R'*T)/100
=(900*(158/27)*3)/100
= Rs.158
New amount will be = Principal + New SI
= Rs.900 + Rs.158
= Rs.1058 - 5 years agoHelpfull: Yes(0) No(0)
- A=P(1+rt) where rate of interest=r/100
from the first line we get
950=900(1+(3*r)/100)
r= 50/27
now interest rate is increased by 4%
so r= 50/27 + 4
=158/27
from the first equation we get =900 * (1 + (( 158 * 3 ) / ( 27 * 100 )))
=1058 - 5 years agoHelpfull: Yes(0) No(0)
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