For what value of k will the equation 2kx2 5kx 2 0 have equal roots A 2 7 B 9

for a 2nd degree equation ax2+bx_c=0 has equal roots the condition is b2-4ac =0
in the given equation
(5k)^2-4*2k*2=0
by solving this equation
we get k=0, k=16/25
8 years agoHelpfull: Yes(43) No(0)

for the roots to be equal b^2-4ac=o is the condition

a=2k b=5k c=2

=> (5k)^2-4(2k)(2)=0
=> 25k^2-16k=0
=>k(25k-16)=0

k=16/25;
8 years agoHelpfull: Yes(12) No(0)
for real and equal roots,
b^2-4ac=0
k=16/25
8 years agoHelpfull: Yes(2) No(3)
B^2=4AC
25k^2=4.2K.2
K=16/25
8 years agoHelpfull: Yes(2) No(0)
roots r equal so b2=4ac
b=2*root(ac)
5k=2*root(4k)
25k2=4*4k
k=16/25
8 years agoHelpfull: Yes(1) No(1)
for equal roots equation should satisfy b2-4ac=0
25k2-16k=0
k=0,k=16/25
so ans is k=16/25
6 years agoHelpfull: Yes(1) No(0)
option c

b^2=4*a*c for equal roots
25k^2=16K
k=16/25
8 years agoHelpfull: Yes(0) No(0)
d2-4ac when root are equal
so 25k2=16k
=>k=16/25
7 years agoHelpfull: Yes(0) No(0)
if roots are equal then b^2=4*a*c
then k=16/25
6 years agoHelpfull: Yes(0) No(1)
25k^2=16k
k=0 it is not possible or
k=16/25
so Option C
6 years agoHelpfull: Yes(0) No(0)
16/25
5 years agoHelpfull: Yes(0) No(0)

For what value of “k” will the equation (2kx2 + 5kx +2)=0 have equal roots?
A. 2/7 B. 9/4 C. 16/25 D. 7/1