A man sets out to cycle from Delhi to Rohtak and at the same time another man starts from Rohtak to cycle to cycle to Delhi. After passing each other they completed their journey in (10/3) hours and (16/3) hours respectively.At what rate does the second man cycle if the first cycle at 8 kmph?
A.6.12 kmph B.6.42 kmph C. 6.22 kmph D. 6.32 kmph

• i have a doubt y cant the solution be S1T1=S2T2 since the distance is equal?
• 8 years agoHelpfull: Yes(24) No(3)
• A's Speed:B's Speed=rootof(b):rootof(a)
  8:x=rootof(10/3):rootof(16/3)
  on solving we get,
  x=2*rootof(10)
  x=2*3.16
  x=6.32kmph
• 8 years agoHelpfull: Yes(23) No(27)
• Ans:D
  speed of the first cycle/speed of the second cycle=root of(time taken by the second cycle/time taken by the first cycle);
  s1/s2=root of(t2/t1)
  8/X=root of(16/3*3/10)
  x=6.32
• 8 years agoHelpfull: Yes(11) No(4)
• If two trains (or bodies) start at the same time from points A and B towards each other and after crossing they take a and b sec in reaching B and A respectively, then:
  (A's speed) : (B's speed) = (sqrt(b) :sqrt( a))
• 7 years agoHelpfull: Yes(5) No(0)
• generally first thing comes in mind as D1= l
  means total distance covered by both the cycles should be same but here is different approach........
  total time taken by first person from d to r is (t +10/3) hr
  total time taken by second person from r to d is (t +16/3) hr
  now we have to find the speed of second person by equating the distance individually covered in 't' time is
  let say there is total distance be D=x+y
  x travell by first and y travell by second in t time.
  equation becames
  y = 8*(10/3).................1
  x=16/3..........................2
  
  and
  
  y=st..............................3
  x=8t..............................4
  s is the speed of second person
  equating 1 , 2 , 3, 4
  we have,
  s=(3/2)t
  st=80/3
  equting above equation
  we get t^2=160/9
  t=(4/3)3.16
  s=2*3.16=6.32kmph ans
• 8 years agoHelpfull: Yes(4) No(10)
• Please provide d solution for dis
• 8 years agoHelpfull: Yes(3) No(0)
• (s1/s2)^2=(16/10)
  (64/s2^2)=1.6
  s2=6.32
• 8 years agoHelpfull: Yes(3) No(6)
• (16x/3)/8=(80/3)/x
  => x=6.32
• 7 years agoHelpfull: Yes(2) No(0)
• this is a general formula =>
  if two cycles (or bodies) start at the same time from points A and B towards each other
  and after crossing they take time a sec and b sec in reaching B and A respectively,
  then:
  (A's speed) : (B's speed) = (sqrt(b) :sqrt( a))
  applying this formula we get,
  x / 8 = root of { (16/3) divide by (10/3) }
  on simplifying
  x / 8 = root of (16 by 10)
  x = 6.32 Ans
• 6 years agoHelpfull: Yes(2) No(1)
• 6.32 is the answer
• 8 years agoHelpfull: Yes(1) No(12)
• its quite confusing ..can any one elaborate please ..?? as we know that distance = speed* time ..we can find the distance from 8km/hr and 10/3 hrs . and distance from rohtak to delhi is same ( constant).
• 8 years agoHelpfull: Yes(1) No(0)
• @suraj kumar- total time is not given here its written that after meeting at a certain point man A took 10/3 hrs and man B took 16/3 hrs
• 6 years agoHelpfull: Yes(1) No(0)
• ans 6.3244 kmph
  
• 7 years agoHelpfull: Yes(0) No(2)
• @kunal
  from where u got this formula
  (A's speed) : (B's speed) = (sqrt(b) :sqrt( a))
  applying this formula we get,
• 6 years agoHelpfull: Yes(0) No(1)
• s1:s2=sqrt (t2):sqrt (t1)
  s2=sqrt(40)=6.32
• 5 years agoHelpfull: Yes(0) No(0)