Elitmus
Exam
Numerical Ability
Age Problem
If we multiply two consecutive three digit prime
numbers we get the result as 'M' and 'S' is square
of a number such that S>M.When we subtract M from S then the result will be:-
a)Perfect Square b)Odd c)Even d)None of the above
I wrote perfect square.Is it right?
Read Solution (Total 3)
-
- yes bro u r ri8
--->**one thing also mention in the Q. there is no Square of Any number between S & M******
-->take 2 consecutive prime no--101 & 103
101*103=10403(i.e M)
square of 102=102*102=10404(i.e S)
S>M
so,10404-10403=1
OR,
similarly
977 & 983 r 2 consecutive prime no
So,977*983=960391
take sqr of 180=960400
960400-960391=9(i.e sqr of 3)
similarly..
u can check more...
- 9 years agoHelpfull: Yes(20) No(4)
- d)none of these
as if we take 191&193
191*193=36863
191*191=36481
when v subtract the two we get 382...which is not a perfect square but is even
then taking 977&983
977*983=960391
976*976=952576
when we subtract them we get 7815 which is odd and not a perfect sq
so we conclude none of these - 9 years agoHelpfull: Yes(7) No(6)
- >>>every prime no. is odd(e.g., 3,5,7,11,13.. 113 and so on )
>>>multiplication of two odd no. is odd( e.g., 3 x 7= 21 i.e odd )
>>> square of any odd no. is odd
>>> sub or add of odd nos. are EVEN
so by these rules,
any three digit prime(odd) and its consecutive prime(odd)
their multiplication and square id ODD
and sub or add of any two ODD is EVEN
so it will be an even no. - 6 years agoHelpfull: Yes(1) No(2)
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