If the length & width of a rectangle is decreased by 50% & then again increase the new length & width by 40%. Calculate the percentage difference between the area of New Rectangle & Original Rectangle.

• 51%r
  let length is l, width is w so area is wl
  after decreament l is i/2 ,w is w/2
  again inc by 40% so l is 7l/10 ,w is 7w/10 so area is 49wl/100
  percentage change is wl-49wl/100=51wl/100
  so 51%
• 8 years agoHelpfull: Yes(11) No(2)
• New rectangle is 51% smaller.
• 8 years agoHelpfull: Yes(2) No(1)
• take a number divisible by 4 and 5
  let the side of the rectangle is 40x and 20y
  now area is 800xy
  
  width is decresed by 50%
  now l=20x and w=10x
  again incresed by 40%
  again l=28x and w=14y
  now area is 392xy
  
  percentage change in area is ((800-392)/800)*100
  51%
  
• 8 years agoHelpfull: Yes(2) No(0)
• take the dimensions of original rectangle as 200*100 (l*b)
  decreased by 50% = 100*50 this is the new dimensions
  increase 40% in new dimensions i.e, 140*70 (40% of 100 is 40 so 100+40=140 and 40% of 50 is 20 so 50+20=70)
  new area 140*70=9800
  original area= 100*200=20000
  difference in area=20000-9800=10200
  % decrease= (10200*100)/20000=51%
  Ans 51%
• 8 years agoHelpfull: Yes(1) No(0)
• 51% smaller
  
  original dimensions:
  200x100
  after 50% decrease:
  100x50
  after 40% increase:
  140x70
  So change in area:
  (200*100)-(140*70)=10200
  %change=(10200*100)/20000=51%
• 8 years agoHelpfull: Yes(1) No(1)
• Decrease by 30%
• 7 years agoHelpfull: Yes(1) No(0)
• 80%
  LET 1ST AREA=XY
  2ND=XY+1/2XY
  3RD=XY+1/2XY+1/5{2ND}
  DIFF.=1ST-3RD;
  =80%
• 8 years agoHelpfull: Yes(0) No(4)
• 19 becayuse
• 8 years agoHelpfull: Yes(0) No(1)
• 51 %
  COZ NEW RWCTANGLE AREA=0.49 OD ORIGINAL RECTANGLE
  HENCE DIFFERNCE IS 51
• 8 years agoHelpfull: Yes(0) No(0)
• 8 * 3 - 3 / 8
• 8 years agoHelpfull: Yes(0) No(0)
• the answer is 51%.let take length and bredth as x and y.then area is xy;now decrease 50% then area is xy/4;again increase area by 40% means area is 49xy/100.thus the result is 51%
• 7 years agoHelpfull: Yes(0) No(0)
• 50% decreased : l/2 * b/2
  40 % increased : 7l/10 * 7b/10
  
  (original - new)/100 = (l*b - 7l/10* 7b/10 ) /100 = 51%
• 7 years agoHelpfull: Yes(0) No(0)
• 49% of the original area
• 7 years agoHelpfull: Yes(0) No(0)