if a:(b+c)=1:3,c:(a+b)=5:7,b:(a+c)=?

• b:(a+c)=1/2
  
  a/(b+c)=1/3 or b=3a-c ---(i) & c/(a+b)=5/7 or 7c=5(a+b), Substituting value of b from (i),
  7c=5(a+3a-c), c=5a/3 ---(ii)
  So b/(a+c)=(3a-c)/[a+(5a/3)] and substituting value of c=5a/3, we have
  b/(a+c)=[3a-(5a/3)]/[a+(5a/3)]=4a/8a=1/2
  
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