ARRAY-SHEET
Q1. main()
{
int n=10;
int a[n];
printf("n %d bytes",sizeof(a));
}
(a) compilation error (b) garbage values (c) 20 bytes (d) 10 bytes

Q2. main()
{
int a[]={1,2,3}, i, sum=0, *p, *q;
q=p=a;
for(i=0;i<3;i++)
{
++*p++;
printf(" %d", q[i]);
}
}
(a) 1 2 3 (b) 2 3 4 (c) all garbage values (d) no output

Q3. main()
{
int a[25];
a[0]=46;
a[24]=50;
printf("%d %d",a[24]-a[0],&a[24]-&a[0]);
}
(a) compilation error (b) 24 24 (c) 46 50 (d) 4 24

Q4. main()
{
int a[2]={10,20}, *p, i=1;
p=&a+1;
p--;
for(;i>=0;)
{
printf("%d ", *p--);
i--;
}
}
(a) 20 10 (b) 10 20 (c) 11 21 (d) 21 11

Q5. main()
{ static int a[]={2,4,6};
static int *p[]={a,a+1,a+2};
int *q[]={a+2,a+1,a} , *ptr, i;
for(i=0;i<3;i++)
a[i]=**p+**q;
for(i=0;i<3;i++)
printf("%d ",a[i]); }
(a) 4 8 12 (b) 12 12 12 (c) 8 14 14 (d) 2 4 6

Q6. main()
{ static int a[]={2,4,6};
static int *p[]={a,a+1,a+2};
int *q[]={a+2,a+1,a}, *ptr, i; ;
for(i=0;i<3;i++)
a[i]=*p[i]+*q[i];
for(i=0;i<3;i++)
printf("%d ",a[i]); }
(a) 4 8 12 (b) 12 12 12 (c) 12 22 22 (d) 8 8 14

Q7. Suppose the array a starts with the base address 170 andarray p starts with the base address 180
main()
{ static int a[]={10,12,14,16,18};
static int *p[]={a,a+1,a+2,a+3,a+4} , **ptr, *s;
ptr=p+0;
s=a+0;
printf("n %u %u %d %d ",s,ptr,*s,**ptr);
ptr++; s++;
printf("n %u %u %d %d ",s,ptr,*s,**ptr);
*ptr++; *++s;
printf("n %u %u %d %d ",s,ptr,*s,**ptr);
++*ptr; ++*s;
printf("n %u %u %d %d ",s,ptr,*s,**ptr);
*ptr++; *s++;
printf("n %u %u %d %d ",s,ptr,*s,**ptr); }

Q8. main() {
int a[5]={10,20,30,40,50},*p;
int i;
p=a;
for(i=0;i<3;i++)
printf(" %.4d ",++p[i]); }
(a) 10 20 30 (b) 0010 0020 0030 (c) 0011 0021 0031 (d) all garbage

Q9. main()
{ int a[][2][3]={ { {1,2,3}, { 4, 5, 6} },
{ {7,8,9}, {10,11,12} }
};
printf("%u ",***a+1+1+2);
printf("%u ", ***(a+1)+1+2);
printf("%u ",**(*(a+1)+1)+2);
printf("%u ",*(*(*(a+1)+1)+2)); }
(a) error (b) 1 12 12 12 (c) 1 10 11 12 (d) 5 10 12 12

Q10. main()
{ int a[]={10,20,30};
int *p[3]={a}, i;
for(i=0;i<3;i++)
printf("%u ",p[i]);
} suppose the base address of array a is 170
(a) 170 172 174 (b) 170 0 0 (c) 170 and garbage addresses (d) no output

Q11. main()
{ float x[3][3][3]={1.5,2.5};
printf("%.2f %.2f",x[0][0][0],x[2][2][2]); }
(a) 1.50 garbage value (b) 1.50 2.50 (c) 0.00 0.00 (d) 1.50 0.00 ( e) none of these

Q12. main()
{ int a[5]={10,20,30,40,50}, *p;
p=a+4;
p[-2]=50;
printf("n%u %d",p[-2],a[2]); }
(a) 30 50 (b) error (c) 30 30 (d) 50 30 (e) none of these

Q13. main()
{ int a[3]={10,20,30},*p;
for(p=a;p<&a[3];p++)
{ *p=p-a;
printf("%d ",*p); }
}
(a) 10 20 30 (b) garbage values (c) 1 2 3 (d) 0 1 2 (e) none of these

Q14. main()
{
int a[3][3];
printf("%u ",&a+0);
printf("%u ",&a+1);
}
if the base address is 65506
(a) 65506 65508 (b) 65506 65518 (c) 65506 65526 (d) 65606 65524

Q15. main()
{
int a[]={10,20,30} , (*p)[3]=a , i;
for(i=0;i<3;i++)
printf("%d ",(*p)[i]);
}
(a) 10 20 30 (b) 10 0 0 (c) 10 10 10 (d) 10 and all garbage values

Q16. What will be the value of a[i] will be printed out in this program?.
main() {
int a[3] , i;
for(i=0;i<3;i++)
{
a[i]=printf("abcde"+i);
printf("%d",a[i]);
} }
(a) 97 98 99 (b) 1 2 3 (c) 5 4 3 (d) all garbage values

Q17. main()
{ int a[]={10,20,30}, i,*p,j=0;
for(i=0;i<3;i++)
{
p=&a[i];
++*p++;
++a[j++];
printf("%d ",a[i]);
}
}
(a) 10 20 30 (b) 11 21 31 (C) 12 22 32 (d) 13 23 33

Q18. main()
{ int a[]={10,11,12}, I;
for(I=0;I<3;I++)
++*a;
for(I=0;I<3;I++)
printf(“%d”,a[I]);
}
(a) error (b) 10 11 12 (c) 11 12 13 (d) 12 13 15 (e) 13 11 12

Q19. main()
{ int a[][3]={1,2,3,4,5,6};
int (*p)[]={a};
printf(“%d %d”,(*p)[1],(*p)[2]);
*p++;
printf(“%d %d”,(*p)[1],(*p)[2]); }
(a) 2 3 5 6 (b) 2 3 4 5 (c) 4 5 0 0 (d) compilation error

Q20 main()
{ char a[ ]="Jyotir";
char b[ ]="Janmay";
char c[10];
c=a;
a=b;
b=c;
printf("%s %s",a,b); }
(a) Jyotir Janmay (b) Janmay Jyotir (c) Jyotir Jyotir (e) error

Q21 main()
{ char *a="Jyotir";
char *b="Janmay";
char *c;
c=a;
a=b;
b=c; printf("n %s %s ",a,b); }
(a) Jyotir Janmay (b) Janmay Jyotir (c) Jyotir Jyotir (d) Janmay Janmay

Q22 main()
{
int *p=&"Janmayjay";
printf("%s",p);
}
(a) Compiolation Error (b) garbage (c) J (d) Janmayjay (e) none of these

Q23 main()
{ char a[10][10];
char *b[10];
char (*c)[10];
printf("n %d %d %d",sizeof(a),sizeof(b),sizeof(c));
}
(a) 100 10 10 (b) 200 20 20 (c) 100 20 2 (d) none of these

Q24. main()
{
char *a[2]={"Jyotir" , "Janmay"};
printf("n%s",*a+1);
printf("n%s",*(a+1));
}
(a) Jyotir Janmay (b) Janmay Janmay (c) yotir Janmay (d) none of thsee

Q25. main()
{ static char *a[]={"Sanjay Sapra", "Janmayjay Sapra", "Jyotirmay Sapra"};
printf("%s",*(a+2)-16); }
(a) Jyotirmay Sapra (b) Sanjay Sapra (c) Janmayjay Sapra (d) none of these

Q26. main()
{ char a[]="AABBCC";
int i;
for(i=0;i<3;i++)
printf("%d",(int)a[i]);
}
(a) compilation error (b) 65 65 66 (c) 65 65 66 66 67 67 (d) 65 66 67

Q27. main()
{ char a[0];
printf("%d",sizeof(a));
}
(a) compilation error (b) 1 (c) 2 (d) 0

Q28. main()
{
char s[ ]={'a','b','c','n','c',''};
char *p,*str,*str1;
p=&s[3];
str=p;
str1=s;
printf("%d",++*p + ++*str1-32);
}

Q29. What will be the output of this program if I store 3 strings
at time of scanf( ). “Sanjay” “Jyotirmay” “Janmayjay”
main( )
{ char *q;
int j;
for (j=0; j<3; j++) scanf(“%s” ,(q+j));
for (j=0; j<3; j++) printf(“%c” ,*(q+j));
for (j=0; j<3; j++) printf(“%s” ,(q+j));
}
(a) S J J Sanjay Jyotirmay Janmayjay (b) S J J
(c) S J J Sanjay anjay njay (d) S J J SJJanmayjay JJanmayjay Janmayjay

Q30 main()
{
char *p;
p="%dn";
p++;
p++;
printf(p-2,300);
}

Q31. main()
{
char *p = “Iyqm”;
char c;
c = ++*p++;
printf(“%c”,c);
printf(“%s”,p);
}

Q32.
void main()
{ printf(“sizeof (void *) = %d n“, sizeof( void *));
printf(“sizeof (int *) = %d n”, sizeof(int *));
printf(“sizeof (double *) = %d n”, sizeof(double *));
printf(“sizeof(struct unknown *) = %d n”, sizeof(struct unknown*));
}

Q33. main()
{ char a[ ]={10,20,30,40,50,60,70,80};
char *ptr;
ptr=&(a+2)[5];
printf(“%d”,*ptr);
}

Q34.
main()
{
char *str;
str=(char*) malloc(12);
strcpy(str,”Jyotirmay”);
printf(“%s”,str);
str=(char*) realloc(str,22);
strcat(str,”Janmayjay”);
printf(“%s”,str);
}

Q35. main( )
{ static char *arr[ ]={ “sanjay”, “balou” , ”Janmay” , ”Jyotir” };
static char **ptr[ ]={ arr+3, arr+2, arr+1, arr};
char ***p=ptr;
**p++;
printf(“%s”,**p);
printf(“%s”,*--*++p);
printf(“%s”,*p[-2]+3);
printf(“%s”,p[-1][-1]+1);
}

Q36. What will be output if you will compile and execute the following c code?
void main()
{ int i=320;
char *ptr=(char *)&i;
printf("%d",*ptr);
}
(a) 320 (b) 1 (c) 64 (d) Compilation error

Q37. What will be output if you will compile and execute the following c code?
void main()
{ int array[]={10,20,30,40};
printf("%d",-2[array]);
}
(a) 60 (b) -30 (c) 60 (d) Garbage value (e) Compilation error

Q38. int main()
{ char str[] = "Programming";
printf("%s ",&str[2]);
printf("%s ",str);
printf("%s ",&str);
}

Q39. What will be output if you will compile and execute the following c code?
void main()
{ int i;
float a=5.2;
char *ptr;
ptr=(char *)&a;
for(i=0;i<=3;i++)
printf("%d ",*ptr++);
}
(a)0 0 0 0 (b)Garbage Garbage Garbage Garbage (c)102 56 -80 32 (d**)102 102 -90 64

Q40. What will be output if you will compile and execute the following c code?
void main()
{
printf("%s","c" "question" "bank");
}
(a) c question bank (b) c (c) bank (**d) cquestionbank (e) Compiler error

Q41. What will be the output of the following program
main( )
{ char a[ ]=”hello”, b[ ]=”hello”;
if(a==b)
printf(“String matched “);
else
printf(“String not matched”);
}

Q42. main( )
{
printf(“%c”, “abcde”[2]);
printf)”%c”,”abcde”+1)[2]);
}

Q43. main( )
{ printf(“%s”, &“abcde”[2]);
printf(”%s”,&”abcde”+1)[2]);
}

Q44. main()
{
static int a[3]={10,20,30},**c,****d;
int *b[]={a,a+1,a+2,a+3,a+4};
c=b;
d=&c;
++*++*c;
printf("%d %d %d",a[0],a[1],a[2]);
}

Q45 main()
{
static int a[3]={10,20,30},***d;
static int *b[]={a,a+1,a+2};
static int **c[]={b,b+1,b+2};
d=c;
++*++*++*d;
printf("%d %d %d",a[0],a[1],a[2]);
}

Q46. main( )
{
if(strcmp(&“abc”,&”abc”))
printf(“matched”);
else
printf(“not matched”);
}
(a) matched (b) not matched (c) no output (d) compilation error

Q47. main( )
{
if(strncmpi(“ramesh”,”RAMNARESH”,3))
printf(“matched”);
else
printf(“not matched”);
}
(a) matched (b) not matched (c) no output (d) compilation error

Q48. What will the output?
main( )
{
int array[ ] = {1, 2, 3, 5, 8, 13, 21, 34, 55};
int sum = 0,i;
for (i = 0; i < 4; i++)
sum += array[array[i]];
printf(“%d”,sum);
}

Q49. What will the output?
main()
{
char *p = NULL;
char *q = 0;
if (p)
printf(" p ");
else
printf("nullp");
if (q)
printf("qn");
else
printf(" nullqn");
}

Q50. int main()
{
int ary[4] = {1, 2, 3, 4};
int *p = ary + 3;
printf("%d %dn", p[-2], ary[*p]);
}

Q51. void main()
{
char a[10][5] = {"hi", "hello", "fellows"};
printf("%d", sizeof(a[1]));
}

Q52. What will be output of following program?
int main(){
char *ptr1 = NULL;
char *ptr2 = 0;
strcpy(ptr1," c");
strcpy(ptr2,"questions");
printf("n%s %s",ptr1,ptr2);
return 0;
}
(a) c question (b) c (null) (c) (null) (null) (d) Compilation error (e) none of these

Q53.
What will be output of following program?
int main(){
int a = 10;
void *p = &a;
int *ptr = p;
printf("%u",*ptr);
return 0;
}
(a) 10 (b) address (c) 2 (d) Compilation error

Q54. What will be output of following program?
int main( )
{
int a,b,c,d;
char *p = ( char *)0;
int *q = ( int *q)0;
float *r = ( float *)0;
double *s = 0;
a = (int)(p+1);
b = (int)(q+1);
c = (int)(r+1);
d = (int)(s+1);
printf("%d %d %d %d",a,b,c,d);
return 0;
}
(a) 2 2 2 2 (b) 1 2 4 8 (c) 1 2 2 4 (d) compilation error

Q55.What will be output of following program?
int main()
{
int a = 5,b = 10,c;
int *p = &a,*q = &b;
c = p - q;
printf("%d" , c);
return 0;
}
(a) 1 (b) 5 (c) -5 (d) Error (e) None of these

Q56. What will be output if you will compile and execute the following c code?
int main()
{
int a[2][4]={3,6,9,12,15,18,21,24};
printf("%d %d %d",*(a[1]+2),*(*(a+1)+2),2[1[a]]);
return 0;
}
(a) 15 18 21 (b) 21 21 21 (c) 24 24 24 (d) Error (e) None of these

Q57. What will be output if you will compile and execute the following c code?
int main()
{
char arr[]="C Question Bank";
char *p;
p+=3;
p=arr;
p+=3;
*p=100;
printf("%s",arr);
return 0;
}
(a) C question Bank (b) C quesdion Bank (c) C qdestion Bank (d) C q100estion Bank

Q58. What will be output the following c code?
int main()
{
int i;
char *arr[4] = {"C","C++","Java","VBA"};
char *(*ptr)[4] = &arr;
for(i=0;i<4;i++)
printf("Address of String %d : %un",i+1,(*ptr)[i]);
return 0;
}

Q59. What will be output the following c code?
int main()
{
int i;
char *arr[4] = {"C","C++","Java","VBA"};
char *(*ptr)[4] = &arr;
for(i=0;i<4;i++)
printf("String %d : %sn",i+1,(*ptr)[i]);
return 0;
}

Q60. What will be output the following c code?
int main()
{
int i;
char *arr[4] = {"C","C++","Java","VBA"};
char *(*ptr)[4] = &arr;
printf("%s",++(*ptr)[2]);
return 0;
}

• 60) ava
  first ptr will point to arr[2],then (*ptr)[2] have value "java",then ++(*ptr)[2] will have "ava".
• 9 years agoHelpfull: Yes(2) No(0)
• 59)String 1 : CnString 2 : C++nString 3 : JavanString 4 : VBAn
  refer to my explanation of 60)
• 9 years agoHelpfull: Yes(1) No(0)
• 1) a
  
  b'coz sizeof() take only constant variable
• 9 years agoHelpfull: Yes(0) No(1)
• 57)C Qdestion Bank
  becoz 100 is the ascii value of 'd'.so the statement
  p=arr;
  p+=3;
  will replace character 'u' by character 'd'.
  initialy the statement p+=3; will have no effect because initially p is pointing to invalid address.
• 9 years agoHelpfull: Yes(0) No(0)