If the perimeter of a rhombus is 52 cm and one of its
diagonals is 24 cm, then the area of the rhombus is

• perimeter of rhombus = 4a (with side a)
  4a=52 then a=13,
  lets length of one diagonal p=24cm,
  lenght of other diagonal is q;
  area of rhombus = pq/2
  using pythogorus theorem a^2= (p/2)^2 + (q/2)^2
  we will get q=10.
  then area=10*24/2=120 sq.cm
• 8 years agoHelpfull: Yes(7) No(0)
• perimeter of rhombus = 4a (with side a)
  4a=52 then a=13,
  lets length of one diagonal p=24cm,
  lenght of other diagonal is q;
  area of rhombus = pq/2
  using pythogorus theorem a^2= (p/2)^2 + (q/2)^2
  we will get q=10.
  then area=10*24/2=120 sq.cm
  
• 8 years agoHelpfull: Yes(3) No(1)
• perimeter=4a
  52=4a
  a=13(side)
  we know that area of the rhombus is
  A=1/2*d1*rootunder(4*a^2-d1^2)
  = 1/2*24*rootunder(4*(13)^2-(24)^2)
  = 12*10
  =120cm^2
• 8 years agoHelpfull: Yes(1) No(0)
• Diagonals of a rhombus bisect each other at 90 degrees
  Half of each diagonal and one side would for a right angled triangle with the side of the rhombus as the hypotenuse
  
  One side is 52cm/4 = 13cm
  Half of given diagonal is 5cm
  
  Half of the other diagonal is √(13² - 5²) = 12cm
  
  The other diagonal is 12cm×2 = 24cm
  
  Area of rhombus = half product of diagonals = (1/2) × 10cm × 24cm = 120cm²
• 7 years agoHelpfull: Yes(1) No(0)
• Perimeter =4a
  4a=52
  a=13
  Diagonals of a rhombus bisect each other at right angles
  So the triangles due to intersection of Diagonals will be right triangles
  So we can get another diagonal as 13*13-12*12=5
  Hence another diagonal =2*5=10
  Area of rhombus =half*d1*d2=1/2*24*10=120
• 7 years agoHelpfull: Yes(0) No(0)