boring a well 60 m depth, the cost is
Rs.4/– for the first meter. The cost of each successive meter
increases by Rs.3/–. What is the cost of boring the entire well?

• as it is increased by 3 rupees so
  4+7+10+13........
  first term a=4
  difference=d=3 then
  60th term=a+59d=181
  total cost=n/2(a+l)=60/2(4+181)=5550
• 8 years agoHelpfull: Yes(25) No(1)
• a=4
  n=60
  d=3
  sum= n/2(2a+(n-1)*d)
  =60/2(2*4+(60-1)*3)
  =30(8+(59*3))
  =5550
• 8 years agoHelpfull: Yes(7) No(2)
• cost per meter increases as: 4,7,10,13...
  they are in A.P. with common diff=3
  60th term (as well is 60 m) would be= a+(n-1)d=> 4+(59*3)=181
  summation Sn= (n/2)(a+l)
  =>30(4+181)=5550/-
• 8 years agoHelpfull: Yes(1) No(1)
• And will 181
• 8 years agoHelpfull: Yes(0) No(0)
• Ans is 181...
  solution by java program..
  public class str {
  
  public static void main(String a[])
  {
  int i,n=4;
  for(i=1;i
• 8 years agoHelpfull: Yes(0) No(1)
• int i,n=4;
  for(i=1;i
• 8 years agoHelpfull: Yes(0) No(1)