you have three dice each side is numbered as 1,2,3,4,5,6 .you have to take a number from user check that number as sum of any side number of these three dice.like we take number as 5 then the possibility are (1,1,3) (1,2,2) (1,3,1) (2,1,2) (2,2,1) (3,1,1) and is 6 possibility. So write to a program for that. You can write program in c.

• source code in c language
  #include
  void main()
  {
  int n,i,j,k;
  printf("enter a num :n ",n);
  scanf("%d",&n);
  for(i=1;i
• 8 years agoHelpfull: Yes(34) No(26)
• #include
  int main()
  {
  int i,j,k,a;
  static int count;
  
  printf("enter the no.n");
  scanf("%d",&a);
  
  for(i=1;i
• 8 years agoHelpfull: Yes(6) No(10)
• import java.util.*;
  /*write a program to print all the possible combinations so that we get the user input */
  public class Dice {
  public static void main(String [] args)
  {
  int a[]={1,2,3,4,5,6};
  int b[]={1,2,3,4,5,6};
  int c[]={1,2,3,4,5,6};
  int user=new Scanner(System.in).nextInt();
  int count=0;
  for(int i=0;i
• 8 years agoHelpfull: Yes(4) No(9)
• //Solution In C++
  
  #include
  using namespace std;
  int main()
  {
  int t;
  int arr[6]={1,2,3,4,5,6};
  cin>>t;
  for(int i=0;i
• 8 years agoHelpfull: Yes(3) No(15)
• #include
  int main()
  {
  int i, j, n,count=0,c,k;
  printf("Enter N: ");
  scanf("%d", &n);
  for(i=1; i
• 7 years agoHelpfull: Yes(2) No(4)
• #include
  int main()
  {
  int N,dice1,dice2,dice3,count=0;
  scanf("%d",&N);
  if(N>=3)
  {
  for(dice1=1;dice1
• 6 years agoHelpfull: Yes(2) No(2)
• import java.util.*;
  class diceprob{
  public static void main(String s[]){
  System.out.println("enter number to check the possiblity");
  Scanner sc=new Scanner(System.in);
  int num=Integer.parseInt(sc.next());
  int a[]={1,2,3,4,5,6};
  int b[]={1,2,3,4,5,6};
  int c[]={1,2,3,4,5,6};
  int count=0;
  if(num18){System.out.println("0");return;}
  else{
  for(int i=0;i
• 7 years agoHelpfull: Yes(1) No(5)
• #include
  
  int main()
  {
  int i, num1, num2, min, hcf=1;
  
  printf("Enter any two numbers to find HCF: ");
  
  scanf("%d %d", &num1, &num2);
  
  min = (num1
• 7 years agoHelpfull: Yes(1) No(3)