A mother with 7 children takes three at a time to a cinema. She goes with every group of three that she with distinct can form. How many times can she go to the cinema with distinct groups of three children. How many times an individual child will go to cinema before the group is repeated.

• 7C3=35 ways mother can go to cinema with distinct groups of three children
  6C2=15 times a individual child will go to cinema before the group is repeated.
  so total 35 and each number is repeating 15 times.
• 9 years agoHelpfull: Yes(16) No(0)
• for first part it is 7C3 ways=35
  for second part we have selected one child.so remaining 2 out of 6 can de done in 6c2 ways=15 ways
• 9 years agoHelpfull: Yes(6) No(1)
• There are (7c3)=35 different groups of three that can be formed. Realizing all of them means 35. 35 trips to the cinema, or 35⋅3=105 children's tickets. Since there are 7 children each of them has visited the cinema 105/7=15=(6c2)) times, namely with every pair of his 6 siblings
• 9 years agoHelpfull: Yes(5) No(0)
• http://math.stackexchange.com/questions/1412705/the-number-of-times-will-an-individual-child-goes-to-the-cinema-before-a-group-i
• 9 years agoHelpfull: Yes(0) No(0)
• It's fourteen
  
• 9 years agoHelpfull: Yes(0) No(1)