8 men can complete a piece of work in 12 days, how many addition men will be required to complete double to work in 6 days.
a) 24
b) 34
C) 36
D) 38

• 8 men work done =12 days
  if single work have to complet in half days imn 6 days
  then doube the worker so it will be 16 men
  then for 2 similar work we required 16+16=32 men
  we have already 8 men
  now we required only 32-8=24 men
• 8 years agoHelpfull: Yes(7) No(0)
• a) 24
  
  For the same work to be completed in 6 days, 8*2=16 men are required(* time halved, men doubled)
  So for double work to be completed in 6 days, total 16*2=32 men are required.
  So additional men required=32-8=24
• 8 years agoHelpfull: Yes(3) No(0)
• ans is 32 >>>
  (8*12*2)/6
• 8 years agoHelpfull: Yes(0) No(3)
• According to question,
  1 work complete in 12 days by 8 men, so in 1 day they will complete 1/(12*8) works by 1 men.
  2 works complete in 6 days, so in 1 day they will complete 2/6 works.
  1/(12*8) works complete by 1 man
  2/6 works complete by (1/(1/(12*8)))*2/6=12*8*2/6=32 men.
  we have already 8 men then we required 32-8=24 men.
• 8 years agoHelpfull: Yes(0) No(2)
• M1D1/W1=M2D2/W2
  8(12)/1= (8+X)*6/2
  =24
• 1 year agoHelpfull: Yes(0) No(0)