the two sides of a triangle are 32 and 68. the area is 960 sq.cm. find the third side of triangle

• we see 68^2-32^2=(68+32)*(68-32)=100*36=60^2
  now (1/2)*60*32=960(match with given options)
  (i.e area of a right angled triangle whose sides are 32,60,68)
  third side=60
• 8 years agoHelpfull: Yes(26) No(35)
• It is not mentioned whether it is right angled triangle or not and also they did not gave the base and height then how can u assume it ?
• 8 years agoHelpfull: Yes(9) No(3)
• it can also be solve heron's formula.but this will be very longer.
  area=sqrt(s(s-a)(s-b)(s-c))=960.
  where s=(a+b+c)/2.
  s-> semiperimeter of triangle.
• 8 years agoHelpfull: Yes(5) No(9)
• 
  1/2×68×32≠≠ 960
  hence hypotenuse = 68m
  So third side = 682−322−−−−−−−−√682−322 = 60m
  
• 8 years agoHelpfull: Yes(3) No(3)
• angle of triangle is 180.but by answer angle is 160.32+68+60=160
• 8 years agoHelpfull: Yes(0) No(22)
• @sailesh kumar how can you assume it is right angle!!!
• 8 years agoHelpfull: Yes(0) No(0)
• assume(a^2-b^2)
  68^2-32^2=(68+32)*(68-32)=100*36=3600
  taking sqrt root on both side
  a-b=60
  third side is:60
  ans:60
  
  
  third side=60
• 5 years agoHelpfull: Yes(0) No(0)