the sum of ages of suresh and his father is 78 years 6 years hence father s age will be

let suresh age be 'x' and father's age is 78-x
6 years hence 2(x+6)=78-x+6
2x+12=84-x=>3x=72=>x=24
the present age of father is 78-24=54 years
8 years agoHelpfull: Yes(1) No(0)
s+f=78;
6 yr hence,
s-6+f-6=78;
s+f=66;
f's age will be twice of sure
x+2x=66;
x=22;
f's present age
f=2x+6;
=2*22+6;
=50
8 years agoHelpfull: Yes(0) No(1)
54 YEARS. S+F=78, F+6=2(S+6) SOLVING BOTH EQNS F=54 YEARS
8 years agoHelpfull: Yes(0) No(0)
Let, Suresh = s & Father = F
.`. (s+6) + 2(s+6) = 78 + 6 + 6
=> s = 24
So, F = 78 - 24
= 54 (Ans)
8 years agoHelpfull: Yes(0) No(0)
Suresh Father

X 46-X ( present age)
X-3 46-X-3 (3 years back)
Or,
X-3 43-X

Now 3 years back the age of father is 4 times of son.

Father's Age = 4 ( Son's Age)
43-X = 4 ( x-3)
43-X= 4X-12
43+12= 4X+X
55 = 5X
X= 11

The present age of suresh is X.
X=11 ans....
7 years agoHelpfull: Yes(0) No(1)

the sum of ages of suresh and his father is 78 years.6 years hence father's age will be twice of suresh's age.find present age of father.