the sum of ages of suresh and his father is 46 years 3 years back father s age was 4

Let suresh age be s yrs and his fathers age be f yrs. By writing as equation
S+F=46 since sum of ages is 46
F-3=4(S-3) 3 yrs back their ages would be S-3 and F-3.
Solving both we get S=11,F=35
8 years agoHelpfull: Yes(13) No(0)

x is son y is father
x+y=46
y-3=4(x-3) =>y=4x-9
put value
4x-9+x=46
x=11,y=35
8 years agoHelpfull: Yes(1) No(0)
11 years
let the age of sureh's father=x
and the age of suresh=y
x+y=46....(i)
x-3=(y-3)4
x-3=4y-12
4y-x=9....(ii)
after solve the eqn (i) and (ii)
we get x=35 & y=11
8 years agoHelpfull: Yes(1) No(0)
current sum of ages=46
3 years ago, suresh age= (-3), father age (-3)
therefore, 3 years ago sum of ages= (-6) = 40

now w.k.t ratio of ages between them is 1:4
the only possible way dividing 40 in 1:4 = 8:32

therefore current age of suresh is (8+3)=11
and his father age is (32+3)=35
suresh age is 11
8 years agoHelpfull: Yes(1) No(0)
11 years. s+f=46. f-3=4(s-3) solving both eqn s=11 years
8 years agoHelpfull: Yes(0) No(1)
let suresh's age 'x' and father's age 46-x
3 years back the ages of father and son is (46-x-3)=4(x-3)
43-x=4x-12=>55=5x=>x=11
suresh's age is 11 years
8 years agoHelpfull: Yes(0) No(0)
x -current age
before 3 years suresh age=x-3
before 3 years father age=x-3
sum=46
before 3 years,so
sum=46-6(bcz suresh age before 3 years,father age before 3 years)
sum=40
4(x-3)+(x-3)=40
5x-15=40
5x=55
x=11
8 years agoHelpfull: Yes(0) No(0)
given that
Suresh + Father= 46
Father-3=4*(Suresh-3)
46-Suresh=4*Suresh-9
gives Suresh=11 years, so Father= 46-11=35 years.
so, answer is 11 years.
7 years agoHelpfull: Yes(0) No(0)

the sum of ages of suresh and his father is 46 years.3 years back father's age was 4 times suresh's age.find present age of suresh.