the sum of ages of suresh and his father is 46 years.3 years back father's age was 4 times suresh's age.find present age of suresh.

• Let suresh age be s yrs and his fathers age be f yrs. By writing as equation
  S+F=46 since sum of ages is 46
  F-3=4(S-3) 3 yrs back their ages would be S-3 and F-3.
  Solving both we get S=11,F=35
• 8 years agoHelpfull: Yes(13) No(0)
• x is son y is father
  x+y=46
  y-3=4(x-3) =>y=4x-9
  put value
  4x-9+x=46
  x=11,y=35
• 8 years agoHelpfull: Yes(1) No(0)
• 11 years
  let the age of sureh's father=x
  and the age of suresh=y
  x+y=46....(i)
  x-3=(y-3)4
  x-3=4y-12
  4y-x=9....(ii)
  after solve the eqn (i) and (ii)
  we get x=35 & y=11
• 8 years agoHelpfull: Yes(1) No(0)
• current sum of ages=46
  3 years ago, suresh age= (-3), father age (-3)
  therefore, 3 years ago sum of ages= (-6) = 40
  
  now w.k.t ratio of ages between them is 1:4
  the only possible way dividing 40 in 1:4 = 8:32
  
  therefore current age of suresh is (8+3)=11
  and his father age is (32+3)=35
  suresh age is 11
• 7 years agoHelpfull: Yes(1) No(0)
• 11 years. s+f=46. f-3=4(s-3) solving both eqn s=11 years
• 8 years agoHelpfull: Yes(0) No(1)
• let suresh's age 'x' and father's age 46-x
  3 years back the ages of father and son is (46-x-3)=4(x-3)
  43-x=4x-12=>55=5x=>x=11
  suresh's age is 11 years
• 8 years agoHelpfull: Yes(0) No(0)
• x -current age
  before 3 years suresh age=x-3
  before 3 years father age=x-3
  sum=46
  before 3 years,so
  sum=46-6(bcz suresh age before 3 years,father age before 3 years)
  sum=40
  4(x-3)+(x-3)=40
  5x-15=40
  5x=55
  x=11
• 7 years agoHelpfull: Yes(0) No(0)
• given that
  Suresh + Father= 46
  Father-3=4*(Suresh-3)
  46-Suresh=4*Suresh-9
  gives Suresh=11 years, so Father= 46-11=35 years.
  so, answer is 11 years.
• 6 years agoHelpfull: Yes(0) No(0)