The ratio of the ages of aunt agatha and uncle Roger is 5:6, the same as the ratio of the ages of their children, Suzanne and Bemard. if the sum of the ages of Suzanne and aunt Agath, five years ago, was 60, what will be the sum of the ages of Bemard and uncle Roger five years, hence?

• 94 years
  
  If present ages of Aunt Agatha=A, Uncle Roger=R, Suzanne=S, Bernard=B, then
  A/R=5/6 ---(i) & S/B=5/6 ---(ii)
  Given (A-5) + (S-5)=60, S+A=70 ---(iii)
  From (i) 6A=5R & from (iii) A=70-S, so 6(70-S)=5R , 420- 6S=5R ---(iv)
  From (ii) 6S=5B, substituting in (iv), 420- 5B= 5R or B+R=84 ---(v)
  So ages of Bernard and Uncle Roger after 5 years= (B+5) +(R+5)=B+R+10 =84+10 =94
• 8 years agoHelpfull: Yes(35) No(1)
• Let ages of aunt nd auncle 5:6 ratio then ages are 5x nd 6x
  In same way chldrn ages 5y nd 6y
  So 5yrs ago aunt, suzn total
  (5x-5)+(5y-5)=60 >> x+y=14
  Then aftr 5yrs ancle,bemard age total
  (6x+5)+(6y+5)=6(x+y)+10=94
• 8 years agoHelpfull: Yes(12) No(1)
• a:r:s:b=5:6:5:6
  a+s=60 ..5 yr ago
  10x=60+10=70...ie x=7;
  r+b=42+42=84 ans
• 8 years agoHelpfull: Yes(0) No(9)
• agatha/roger=5:6=suzanne/bemard
  agatha+suzanne 5 years ago=60 means-> (5x-5)+(5x-5)=60
  10X=70 therefore x=7;
  we need bemard+roger=6X+6x=12x
  as x=7;
  12*7=84;
  
• 8 years agoHelpfull: Yes(0) No(6)
• A-> agatha, R->Roger, S-> suzanne, B->bemard
  it same as ratio, A:R::S:B= 5:6::5:6
  A + S, 5yrs ago = (5x-5) +(5x-5)= 60
  10x=60+10=70
  X=7
  B+R = ? // five years hence
  (6x+5) + (6x+5)= > (42 +5) + (42+5)= 94.....
• 7 years agoHelpfull: Yes(0) No(0)